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我正在尝试加入两个表customersloan. 所以我的模型是:

if($type == 'society'):
        $this->db->select('customers.customer_id,customers.customer_name,customers.customer_address,loan.loan_amount,loan.grant_date');
        $this->db->from('customers');
        $this->db->join('loan','loan.customer_id = customers.customer_id');
        $this->db->where('loan.customer_type',$type);
        $result = $this->db->get();
        endif;

        return $result;

和控制器:

$loan_customers_society = $this->loan_transaction_model->show_all_loan_customers($type = 'society');
var_dump($loan_customers_society);

但输出如下所示:

object(CI_DB_mysql_result)[19]
  public 'conn_id' => resource(36, mysql link persistent)
  public 'result_id' => resource(40, mysql result)
  public 'result_array' => 
    array
      empty
  public 'result_object' => 
    array
      empty
  public 'custom_result_object' => 
    array
      empty
  public 'current_row' => int 0
  public 'num_rows' => int 3
  public 'row_data' => null

这个输出是干什么用的?我将如何获得我想要的结果?

4

1 回答 1

3

CI ActiveRecordget()方法不返回查询结果,它产生查询并返回 CI 结果对象。

为了得到结果,你需要使用result()orresult_array()方法:

$query  = $this->db->get();
$result = $query->result_array();

// var_dump($result);

查看CI 用户指南中的生成查询结果以获取更多信息。

于 2013-09-06T10:29:46.450 回答