7

我目前正在开发一个从我的核心数据设置中动态填充选择器视图的程序。我的一切都在数据方面工作，但我现在遇到的问题是我的标签上的格式。

选择器在操作表中显示了它自己的工具栏，工具栏右侧有一个按钮。它的初始状态是可见 2 个刻度盘。按下按钮时，它变为 3 个刻度盘。

- (UIView *)pickerView:(UIPickerView *)pickerView viewForRow:(NSInteger)row forComponent:(NSInteger)component reusingView:(UIView *)view
{
    UILabel *pickerLabel = (UILabel *)view;

    CGSize limitSize = CGSizeMake(100.0f, 45.0f);
    CGSize textSize;
    CGRect labelRect;
    NSString *title = @"";


    switch (numberOfComponents){
        case 2:
        {
            ...gets strings from fetched data (varying length from 4 to 20+)
                    title = someString
        }
        case 3:
        {
            ...same as above but for the second set of data.
                    title = someString
        }           
    }


    textSize = [title sizeWithFont:[UIFont systemFontOfSize:14] constrainedToSize:limitSize lineBreakMode:UILineBreakModeWordWrap];
    labelRect = CGRectMake(0, 0, textSize.width, textSize.height);
    NSLog(@"length:%i title:%@",[title length],title);
    NSLog(@"h:%f w:%f",textSize.height,textSize.width);
    if (pickerLabel == nil)
    {
        pickerLabel = [[[UILabel alloc] initWithFrame:labelRect] autorelease];
        [pickerLabel setFont:[UIFont systemFontOfSize:14]];
        [pickerLabel setBackgroundColor:[UIColor clearColor]];
        [pickerLabel setLineBreakMode:UILineBreakModeWordWrap];
        [pickerLabel setTextAlignment:UITextAlignmentCenter];
        [pickerLabel setNumberOfLines:2];
    }

    [pickerLabel setText:title];    

    return pickerLabel;
}

我手动将行高设置为 32.0f。我得到了非常奇怪的结果，因为第二个组件中的一些标签工作正常。但其他人根本没有换行，有些人只是显示为空白。

即：球芽甘蓝包裹好（右组件）。但牛奶和奶油不显示（只有牛奶可见）蔬菜根本不出现。我的代码哪里出错了？

4

3 回答 3

2

我设法让它表现得很好。我通过删除更改了最后一部分


textSize = [title sizeWithFont:[UIFont systemFontOfSize:14] constrainedToSize:limitSize lineBreakMode:UILineBreakModeWordWrap];

我手动设置框架


labelRect = CGRectMake(0,0,100.0,36.0);

不知道为什么这在动态调整大小时不起作用。

于 2009-12-09T02:38:48.523 回答
2

这是 swift 的版本。

 func pickerView(pickerView: UIPickerView, viewForRow row: Int, forComponent component: Int, reusingView view: UIView!) -> UIView {
    var label : UILabel
    if view == nil {
        label = UILabel(frame: CGRect(x: 0, y: 0, width: 0, height: UIFont.systemFontOfSize(UIFont.systemFontSize()).lineHeight * 2 * UIScreen.mainScreen().scale))
        label.textAlignment = NSTextAlignment.Center
        label.numberOfLines = 2
        label.lineBreakMode = NSLineBreakMode.ByWordWrapping
        label.autoresizingMask = UIViewAutoresizing.FlexibleWidth
    } else {
        label = view as UILabel
    }
    label.text = line1 + "\n" + line2

    return label;
}

func pickerView(pickerView: UIPickerView, rowHeightForComponent component: Int) -> CGFloat {
    return UIFont.systemFontOfSize(UIFont.systemFontSize()).lineHeight * 2 * UIScreen.mainScreen().scale
}
于 2014-10-03T23:26:53.030 回答
0

我更正了您的代码，以使标签宽度适合选择器宽度。我使用了koushi方法。现在效果很好。请参阅此处附加的我的代码。

 - (UIView *)pickerView:(UIPickerView *)pickerView viewForRow:(NSInteger)row forComponent:(NSInteger)component reusingView:(UIView *)view
 {

//assegna i nomi alle caselle del picker e assegna anche la dimensione del font e del rettangolo che contiene le scritte

UILabel *pickerLabel = (UILabel *)view;
CGRect labelRect;

NSString *title=@"";
switch (numberOfComponents){
case 2:
{
    ...gets strings from fetched data (varying length from 4 to 20+)
                title = someString
}
case 3:
{
    ...same as above but for the second set of data.
                title = someString
}           
 }

CGFloat labelWidth=pickerView.frame.size.width-50;
labelRect = CGRectMake( 0,0,labelWidth,45.0);

if (pickerLabel == nil)
{
    pickerLabel = [[UILabel alloc] initWithFrame:labelRect];
    [pickerLabel setFont:[UIFont systemFontOfSize:16]];
    [pickerLabel setBackgroundColor:[UIColor clearColor]];
    [pickerLabel setNumberOfLines:2];
}

[pickerLabel setText:title];    
return pickerLabel;

  }

关于您的原始代码：我认为拥有一个具有不同矩形大小的元素的选择器不利于外观（用户体验）问题。我怀疑不同的标签矩形大小会在您的代码中产生问题。如果您要显示的文本可以大于定义的矩形，我认为您应该使用不同的应用程序结构方法。

注意：在我的应用程序中，我使用选择器标签属性来识别选择了哪个选择器，因为我的视图中有多个选择器。出于这个原因，我用以下代码替换了代码中的“switch”语句：

  if (pickerView.tag==1)
    title= globalSubcategoryArray[row];
  else
    title= globalAreasName[row];

显然我还添加了：

 -(NSInteger)pickerView:(UIPickerView *)pickerView numberOfRowsInComponent:(NSInteger)component {
if (pickerView.tag==1)
    return globalSubcategoryArray.count;
else    
    return globalAreasName.count;
 }

 -(NSInteger)numberOfComponentsInPickerView:(UIPickerView *)pickerView {
return  1;
 }



 -(void)pickerView:(UIPickerView *)pickerView didSelectRow:(NSInteger)row inComponent:(NSInteger)component {
if (pickerView.tag==1){
    self.subcategoryTextview.text = globalSubcategoryArray[row];
    globalSelectedSubcategoryIndex=row;
    [self.subcategoryTextview resignFirstResponder];

}else{
    self.areaTextview.text= globalAreasName[row];
    globalSelectedAreaIndex=row;
    [self.areaTextview resignFirstResponder];
}

 }
于 2015-05-24T12:15:17.537 回答