mysql - MySQL SELECT 仅当值高于 XXX 的下一个最高值时

Question

我想在 MySQL 表（unix 时间戳）中选择一个字段，前提是大于下一个最高值 7200。怎么做？

我的意思是这样的：

SELECT id FROM registers WHERE time IS BIGGER than NEXT time BY 7200？

表寄存器：id (int_8)、time(int_11)、description(text)

例子：

1, 127586113, This is description
2, 127587399, This is description (NEXT HIGHEST)
3, 127588524, This is description (HIGHEST, LET'S SAY EQUAL TO NOW())

Answer 1

select id from registers
WHERE time = ( select min(time)
                        from registers
                        where time > 7200);

如果我正确理解了这个问题，应该这样做。

Answer 2

select id 
from registers r
where not exists 
      (select 1 from registers where time < r.time and time > r.time - 7200)