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我正在与我的 ios 应用程序中的服务器通信。我有以下打开警报视图的方法。我想在应用程序从服务器获取响应时显示加载视图。

- (void) showDetailedQuestion:(id)sender
{
       //loading view                  
        self.loading_alert = [[UIAlertView alloc] initWithTitle:@"Loading\nPlease Wait..." message:nil delegate:self cancelButtonTitle:nil otherButtonTitles: nil];
        [self.loading_alert show];

        UIActivityIndicatorView *indicator = [[UIActivityIndicatorView alloc] initWithActivityIndicatorStyle:UIActivityIndicatorViewStyleWhiteLarge];

        // Adjust the indicator so it is up a few pixels from the bottom of the alert
        indicator.center = CGPointMake(loading_alert.bounds.size.width / 2, loading_alert.bounds.size.height - 50);
        [indicator startAnimating];
        [self.loading_alert addSubview:indicator];

    UIButton *btn = (UIButton*)sender;
    int indx = btn.tag;

    NSLog(@"tag:%d",indx);
    answerAnQuestion *vc = [self.storyboard instantiateViewControllerWithIdentifier:@"Answer"];

    vc.modalTransitionStyle = UIModalTransitionStyleFlipHorizontal ;
    vc.que_id = [self.que_id valueForKey:[NSString stringWithFormat:@"%d",indx]];
    vc.qid_list = self.que_id;
    vc.crnt = indx;

    [self presentViewController:vc animated:YES completion:nil];
    [self.loading_alert dismissWithClickedButtonIndex:0 animated:YES];
}

在另一个 answerAnQuestion.m

- (void)viewDidLoad
{
            NSString *address = [NSString stringWithFormat:@"%@%@%@%@%@%@%@", path,@"questions/",que_id,@"?token=",token,@"&user_id=",usrId];
    NSURL *URL = [NSURL URLWithString:address];
    NSLog(@"%@",address);

    [NSURLRequest setAllowsAnyHTTPSCertificate:YES forHost:[URL host]];
    NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:URL cachePolicy:NSURLCacheStorageAllowedInMemoryOnly
                                                       timeoutInterval:60.0];
    [request setHTTPMethod:@"GET"];
    responseData = [[NSMutableData alloc] init];

    NSURLResponse *response = nil;
    NSError *error = nil;
    NSData *data = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error]; 

    if (data) 
    {
        NSHTTPURLResponse *httpResponse = (NSHTTPURLResponse*) response;
        //If you need the response, you can use it here
        int statuscode = [httpResponse statusCode];
        NSString *responseMsg = [NSHTTPURLResponse localizedStringForStatusCode:statuscode];
        NSLog(@" Status code: %d",statuscode );
        NSLog(@" Status msg: %@",responseMsg );

    }
    else 
    {
        // Handle error by looking at response and/or error values
        NSLog(@"%@",error);
    }
}

我的问题是警报视图仅在视图更改时显示片刻。它应该在我单击按钮时打开。可能是什么原因？如何解决这个问题？

编辑1：

如果我向服务器发出异步请求，那么我无法在我的 tableview 中设置这些数据。我只能在发送同步请求时在我的表格视图中设置这些数据，但它会阻止应用程序。为什么会这样？

任何帮助将不胜感激。谢谢你。

4

2 回答 2

1

您在主线程上发送 SynchronousRequest，因此它阻塞了您的 UI 线程。阅读多线程，您将获得有关此的各种教程。我可以建议你选择 GCD 或 NSOperation 和 NSOperationQueue。谷歌搜索上述任何一个，你都会得到相同的各种样本。

或者您可以按如下方式发送异步请求...

[NSURLConnection sendAsynchronousRequest:request queue:[[NSOperationQueue alloc] init] completionHandler:^(NSURLResponse *response, NSData *data, NSError *error){
        //Write code you want to call when data is received,
        //Like dismissing loading view and populating UI.
 }];

更新：

//Display alert view, before sending your request..
[alertview show];
//send first request
[NSURLConnection sendAsynchronousRequest:request1 queue:[[NSOperationQueue alloc] init] completionHandler:^(NSURLResponse *response, NSData *data, NSError *error){

            //Write code you want to call when data is received,
            //send second request
[NSURLConnection sendAsynchronousRequest:request2 queue:[[NSOperationQueue alloc] init] completionHandler:^(NSURLResponse *response, NSData *data, NSError *error){

            //Write code you want to call when data is received,
            //send third request
[NSURLConnection sendAsynchronousRequest:request3 queue:[[NSOperationQueue alloc] init] completionHandler:^(NSURLResponse *response, NSData *data, NSError *error){
            //Write code you want to call when data is received,
            //dismiss alert view on main thread
dispatch_async(getmainqueue, ^(void) { 
// dismiss alert view... 
});
     }];
     }];

     }];
于 2013-08-30T11:33:23.367 回答
0

我曾使用过 Nuzat Zari 代码，为此我感谢他，但在嵌套的“sendAsynchronousRequest”之间也遇到了一些核心数据操作的问题（出现一些奇怪的线程和内存错误），所以我的解决方案是取消对“ sendAsynchronousRequest”并使用一些主线程变量验证。

@interface myMainThreadClass
@property (nonatomic,assign) NSInteger *currentAsyncTasks;
@end
@implementation

// Use init or viewDidLoad to make "currentAsyncTasks=0"!!

-(void)method
{
[self showLoadingAlert]; //or some ui update function

currentAsyncTasks++;
[NSURLConnection sendAsynchronousRequest:urlRequest queue:[[NSOperationQueue alloc] init] completionHandler:^(NSURLResponse *response, NSData *data, NSError *error){
    //do something with data
    dispatch_async(dispatch_get_main_queue(), ^(void) {
        [self dismissAlertInFinalTask] 
    });
}];
 currentAsyncTasks++;
[NSURLConnection sendAsynchronousRequest:urlRequest2 queue:[[NSOperationQueue alloc] init] completionHandler:^(NSURLResponse *response, NSData *data, NSError *error){
    //do something with data 
    dispatch_async(dispatch_get_main_queue(), ^(void) {
        [self dismissAlertInFinalTask] 
    });
}];

 currentAsyncTasks++;
[NSURLConnection sendAsynchronousRequest:urlRequest3 queue:[[NSOperationQueue alloc] init] completionHandler:^(NSURLResponse *response, NSData *data, NSError *error){

   //do something with data 
    dispatch_async(dispatch_get_main_queue(), ^(void) {
        [self dismissAlertInFinalTask] 
    });
}];
}
-(void)dismissAlertInFinalTask
{
    currentNetworkTasks--;
    if (currentNetworkTasks == 0)
    {
        [self dismissLoadingAlert];//or some ui update function;
    }
}
@end

我还想知道是否有人设法使用 NSURLConnection 委托 NSURLConnectionDataDelegate 和 ui 调用来执行多个请求。

于 2013-11-25T05:52:55.553 回答