我在 Linux 中有一些带有一些行的文件，例如：
2013/08/16,name1,,5000,8761,09:00,09:30
2013/08/16,name1,,5000,9763,10:00,10:30
2013/08/16,name1,,5000,8866,11:00,11:30
2013/08/16,name1,,5000,5768,12:00,12:30
2013/08/16,name1,,5000,11764,13:00,13:30
2013/08/16,name2,,5000,2765,14:00,14:30
2013/08/16,name2,,5000,4765,15:00,15:30
2013/08/16,name2,,5000,6765,16:00,16:30
2013/08/16,name2,,5000,12765,17:00,17:30
2013/08/16,name2,,5000,25665,18:00,18:30
2013/08/16,name2,,5000,45765,09:00,10:30
2013/08/17,name1,,5000,33765,10:00,11:30
2013/08/17,name1,,5000,1765,11:00,12:30
2013/08/17,name1,,5000,34765,12:00,13:30
2013/08/17,name1,,5000,12765,13:00,14:30
2013/08/17,name2,,5000,1765,14:00,15:30
2013/08/17,name2,,5000,3765,15:00,16:30
2013/08/17,name2,,5000,7765,16:00,17:30
我的列分隔符是“ ,”，在第三列（当前,,）中，我需要在同一天内的条目号。例如，日期 2013/08/16 我有 11 行，日期 2013/08/17 有 7 行，所以我需要添加数字，例如：
2013/08/16,name1,1,5000,8761,09:00,09:30
2013/08/16,name1,2,5000,9763,10:00,10:30
2013/08/16,name1,3,5000,8866,11:00,11:30
2013/08/16,name1,4,5000,5768,12:00,12:30
2013/08/16,name1,5,5000,11764,13:00,13:30
2013/08/16,name2,6,5000,2765,14:00,14:30
2013/08/16,name2,7,5000,4765,15:00,15:30
2013/08/16,name2,8,5000,6765,16:00,16:30
2013/08/16,name2,9,5000,12765,17:00,17:30
2013/08/16,name2,10,5000,25665,18:00,18:30
2013/08/16,name2,11,5000,45765,09:00,10:30
2013/08/17,name1,1,5000,33765,10:00,11:30
2013/08/17,name1,2,5000,1765,11:00,12:30
2013/08/17,name1,3,5000,34765,12:00,13:30
2013/08/17,name1,4,5000,12765,13:00,14:30
2013/08/17,name2,5,5000,1765,14:00,15:30
2013/08/17,name2,6,5000,3765,15:00,16:30
2013/08/17,name2,7,5000,7765,16:00,17:30
我需要在 bash 中完成。我该怎么做？