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我的程序有些困难。我想要的只是从表中获取一些具有这种简单结构的对象：

mysql> describe tb_rasa;
+--------+-------------+------+-----+---------+----------------+
| Field  | Type        | Null | Key | Default | Extra          |
+--------+-------------+------+-----+---------+----------------+
| id     | int(11)     | NO   | PRI | NULL    | auto_increment |
| nazwa  | varchar(50) | YES  |     | NULL    |                |
| symbol | varchar(4)  | NO   | UNI | NULL    |                |
+--------+-------------+------+-----+---------+----------------+

在我的豆类中，我有：

@PostConstruct
public void init() {    
    rasa = rasaEJB.wyswietlRase(1);
}

在 RasaEJB 中：

public RasaSl wyswietlRase(Integer id) {
    System.out.println("RasaEJB.wyswietlRase(id)");     
    RasaSl rasa = rasaDao.find(id);     
    return rasa;        
}

RasaSl 实体看起来像：

@Entity
@Table(name="tb_rasa")
 public class RasaSl implements Serializable {

/**
 * 
 */
private static final long serialVersionUID = -4682401385263402475L;

@Id
@Column(name="id")
@GeneratedValue(strategy = GenerationType.AUTO)
private Integer id;

@Column(name="nazwa",columnDefinition="varchar(50)")
private String nazwa;

@Column(name="symbol", columnDefinition="varchar(4)")
private String symbol;

@OneToMany(mappedBy="rasaSl", cascade=CascadeType.PERSIST)
private List<RasaStatystyka> modyfikatory = new ArrayList<RasaStatystyka>();

public String getNazwa() {
    return nazwa;
}

public void setNazwa(String nazwa) {
    this.nazwa = nazwa;
}

public String getSymbol() {
    return symbol;
}

public void setSymbol(String symbol) {
    this.symbol = symbol;
}

public List<RasaStatystyka> getModyfikatory() {
    return modyfikatory;
}

public void setModyfikatory(List<RasaStatystyka> modyfikatory) {
    this.modyfikatory = modyfikatory;
}

public Integer getId() {
    return id;
}

public void setId(Integer id) {
    this.id = id;
}

}

我完全知道什么会造成这个错误：

RasaEJB.wyswietlRase(id)
[EL Info]: 2013-08-29 16:45:18.207--ServerSession(1816969462)--EclipseLink, version: Eclipse Persistence Services - 2.5.0.v20130507-3faac2b
[EL Info]: 2013-08-29 16:45:18.588--ServerSession(1816969462)--file:/D:/usr/java/moje/system/.metadata/.plugins/org.eclipse.wst.server.core/tmp4/wtpwebapps/EclipseJPA2-war/WEB-INF/lib/EclipseJPA2-jpa-0.01.jar_persistenceUnit login successful
[EL Warning]: 2013-08-29 16:45:18.688--UnitOfWork(1358566974)--Exception [EclipseLink-4002] (Eclipse Persistence Services - 2.5.0.v20130507-3faac2b): org.eclipse.persistence.exceptions.DatabaseException
Internal Exception: com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: Unknown column 'id' in 'field list'
Error Code: 1054
Call: SELECT id, nazwa, symbol FROM tb_rasa WHERE (id = ?)
bind => [1 parameter bound]
Query: ReadObjectQuery(name="readRasaSl" referenceClass=RasaSl sql="SELECT id, nazwa, symbol FROM tb_rasa WHERE (id = ?)")

请帮忙。

4

0 回答 0