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我刚刚开始探索 Spinner 控件。我几乎已经实现了我想要的，但只缺少最后一步。这是我到目前为止所做的。

对于这个例子，我有一个非常简单的类：

[Serializable]
public class Merchant
{
    public Int64 MerchantId { get; set; }
    public String ShopName { get; set; }

    public override string ToString()
    {
        return ShopName;
    }
}

这是我放置 Spinner 的 axml：

<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:orientation="vertical"
    android:layout_width="1280dip"
    android:layout_height="800dip">
    <TextView
        android:text="Select a merchant:"
        android:layout_width="fill_parent"
        android:layout_height="wrap_content"
        android:id="@+id/lblSelect"
        android:layout_marginLeft="30dip"
        android:layout_marginTop="30dip"
        android:textSize="42dip" />
    <Spinner
        android:id="@+id/spinMerchant"
        android:layout_width="1000dip"
        android:layout_height="wrap_content"
        android:layout_below="@id/lblSelect"
        android:prompt="@string/spinner_prompt"
        android:layout_centerHorizontal="true"
        android:minHeight="20dip" />
</RelativeLayout>

我的代码是：

    protected override void OnCreate (Bundle bundle)
    {
        base.OnCreate (bundle);

        // Create your application here
        this.SetContentView(Resource.Layout.MerchantSelect);

        List<Merchant> lstMerchant = new List<Merchant> ();
        lstMerchant.Add (new Merchant() { ShopName = "First Shop", MerchantId = 11 });
        lstMerchant.Add (new Merchant() { ShopName = "Second Shop", MerchantId = 12 });

        Spinner spinner = this.FindViewById<Spinner>(Resource.Id.spinMerchant);
        ArrayAdapter adapter = new ArrayAdapter (this, Android.Resource.Layout.SimpleSpinnerItem, lstMerchant);
        spinner.ItemSelected += new EventHandler<AdapterView.ItemSelectedEventArgs> (spinner_ItemSelected);

        spinner.Adapter = adapter;
    }

    private void spinner_ItemSelected (object sender, AdapterView.ItemSelectedEventArgs e)
    {
        Spinner spinner = (Spinner)sender;
        //Merchant merch = (Merchant)spinner.SelectedItem;
        string toast = string.Format ("Selected text is {0}", spinner.GetItemAtPosition (e.Position));
        Toast.MakeText (this, toast, ToastLength.Long).Show ();
    }

做出选择后，我想立即获取所选文本及其背后的 ID。我得到了文本，spinner.GetItemAtPosition (e.Position)但我似乎找不到任何可以给我 ID 的东西。如果我尝试这样做，Merchant merch = (Merchant)spinner.SelectedItem;我会得到一个例外：Cannot convert type 'Java.Lang.Object' to 'Merchant'.

请让我知道如何实现。

谢谢。

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1 回答 1

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微调器只知道文本，因为这就是您在ToString()方法中所拥有的。提供微调器数据的适配器不知道它正在处理Merchant对象。要获得实际的 Merchant 对象，您必须使您List<Merchant> lstMerchant成为班级的成员。

然后更改您的选择处理程序：

private void spinner_ItemSelected (object sender, AdapterView.ItemSelectedEventArgs e)
    {
        Spinner spinner = (Spinner)sender;
       // Get the ID from your model.
        Merchant merch = this.lstMerchant[e.Position];
        var id = merch.MerchantId;
        string toast = string.Format ("Selected text is {0}", spinner.GetItemAtPosition (e.Position));
        Toast.MakeText (this, toast, ToastLength.Long).Show ();
    }
于 2013-08-28T11:09:28.520 回答