有没有办法通过仅将 XML 处理为字符串来转义 XML 标记内容中的 XML 特殊字符?可以使用正则表达式(regexp)来完成吗?尝试从字符串创建新 XML() 时出现格式错误的 XML 的运行时错误,因为它在某些标记内包含“<”字符。
问问题
536 次
1 回答
2
你可以使用这样的东西:
public static function escapeXMLTagContents(a_string:String):String{
var l_indexOfSpecialChar:int = -1,
l_tagsMatch:RegExp =/<(\?|[a-zA-Z_]{1}|\/{1})[^<]*?>/g,
l_tags:Array = [],
l_tagCharacterIndexes:Array = [],
l_stringCopy:String = new String(a_string),
i:int = -1,
l_replaceArray:Array = [],
l_return:String = "",
l_tagCharIndex:int = -1,
l_replaceChar:String = "";
l_replaceArray.push("&|&");
l_replaceArray.push("<|<");
l_replaceArray.push(">|>");
l_replaceArray.push("\"|"");
l_replaceArray.push("'|'");
l_tags = a_string.match(l_tagsMatch);
i = l_tags.length;
while (--i > -1){
var l_tagText:String = l_tags[i];
var l_startIndex:int = l_stringCopy.lastIndexOf(l_tagText);
var l_endIndex:int = l_startIndex + (l_tagText.length - 1);
for (var j:int = l_startIndex; j <= l_endIndex; j++){
if(l_tagCharacterIndexes.indexOf(j) < 0){
l_tagCharacterIndexes.push(j);
}
}
l_stringCopy = l_stringCopy.substring(0, l_startIndex);
}
l_return = new String(a_string);
for each (l_replaceChar in l_replaceArray){
l_stringCopy = new String(l_return);
while ((l_indexOfSpecialChar = l_stringCopy.lastIndexOf(l_replaceChar.charAt(0))) > -1) {
// determine if it char needs to be escaped (i.e is inside tag contents)
if(l_tagCharacterIndexes.indexOf(l_indexOfSpecialChar) == -1){
l_return = l_return.substring(0, l_indexOfSpecialChar) + l_replaceChar.split("|")[1] + l_return.substring(l_indexOfSpecialChar+1);
// adjust indexes
for (i = 0; i < l_tagCharacterIndexes.length; i++) {
l_tagCharIndex = l_tagCharacterIndexes[i];
if(l_tagCharIndex >= l_indexOfSpecialChar) {
l_tagCharacterIndexes[i] = l_tagCharacterIndexes[i] + String(l_replaceChar.split("|")[1]).length-1; // -1 from the old characther "&,<,>," or '"
}
}
}
l_stringCopy = l_stringCopy.substring(0, l_indexOfSpecialChar);
}
}
return l_return;
}
于 2013-08-27T15:18:29.173 回答