1

我有 UIActionSheet。它显示数组中的标题。当我单击按钮时，什么都不会发生。我也使用了 NSLog。但它没有显示任何东西。按钮标题从数组中显示。但只有点击不起作用

代码：

行动单：

TSActionSheet *actionSheet = [[TSActionSheet alloc] initWithTitle:@"Design"];

         for (int i = 0; i<[catearray count]; i++ ) {

             [actionSheet addButtonWithTitle:[catearray objectAtIndex:i] block:^{





              }];

         }

按钮点击：

-(void)actionSheet:(UIActionSheet *)actionSheet clickedButtonAtIndex:(NSInteger)buttonIndex {
    if (buttonIndex == 0) {

        NSLog(@"button");



    } else if (buttonIndex == 1) {

        NSLog(@"button 1");


    } else if (buttonIndex == 2) {


          NSLog(@"button 2");

    } else if (buttonIndex == 3) {

    }





}

大批：

  if (sqlite3_open([path UTF8String], &database) == SQLITE_OK) {

            const char *sql = "SELECT id,cat_name FROM categories";

            NSLog(@"sql is %s",sql);

            sqlite3_stmt *statement;
            //  int catID = 0;
            if (sqlite3_prepare_v2(database, sql, -1, &statement, NULL) == SQLITE_OK) {
                // We "step" through the results - once for each row.
                while (sqlite3_step(statement) == SQLITE_ROW) {


                    category = [[NSString alloc] initWithUTF8String:
                               (const char *) sqlite3_column_text(statement, 1)];
                    NSLog(@"catName is %@",category);

                    [catearray addObject:category];


                    // catID = sqlite3_column_int(statement, 0);
                }
            }


            sqlite3_finalize(statement);
        }

        else {
            sqlite3_close(database);
            NSAssert1(0, @"Failed to open database with message '%s'.", sqlite3_errmsg(database));
            // Additional error handling, as appropriate...
        }
4

2 回答 2

1

您正在使用一个名为 TSActionSheet 的库和默认 UIActionSheetDelegate 中未调用的操作

所以你必须将你的动作转移到这样的方法

-(void)actionSheetClickedButtonAtIndex:(int)buttonIndex {

     if (buttonIndex == 0) {
        NSLog(@"button");



    } else if (buttonIndex == 1) {

        NSLog(@"button 1");


    } else if (buttonIndex == 2) {


          NSLog(@"button 2");

    } else if (buttonIndex == 3) {

    }
}

然后像这样在你的块上调用这个方法

TSActionSheet *actionSheet = [[TSActionSheet alloc] initWithTitle:@"Design"];

         for (int i = 0; i<[catearray count]; i++ ) {

             [actionSheet addButtonWithTitle:[catearray objectAtIndex:i] block:^{

                    [self actionSheetClickedButtonAtIndex:i];



              }];

         }
于 2013-08-26T11:00:41.467 回答
1

不，您没有使用 UIActionSheet，您使用的是 TSActionSheet，它不是 UIActionSheet 的子类（它是 UIView 的子类），因此不期望它实现 UIActionSheetDelegate 协议。请注意，当您向 TSActionSheet 添加按钮时，传递给按钮的参数之一是块。这是您放置希望在点击按钮时执行的代码的地方。

[actionSheet addButtonWithTitle:@"button one" color:[UIColor whiteColor] titleColor:[UIColor darkGrayColor] borderWidth:1 borderColor:[UIColor grayColor] block:^{
        NSLog(@"pushed button one");
}];
于 2013-08-26T10:58:15.180 回答