3

我有一个类似于这个的存储过程,当我尝试保存它时,我收到了这个错误:

未声明的变量:my_column

CREATE PROCEDURE p (OUT column_param VARCHAR(25))
BEGIN
    SELECT my_column INTO coumn_param limit 1;
END;

为什么我不能选择要返回的列?

这是我在程序中的实际查询:

select latitude into lat, longitude into lon
from cities cc
inner join countries c on cc.country_id = c.country_id
inner join regions r on cc.region_id = r.region_id and c.country_id = r.country_id
left join locations l on cc.city_id = l.city_id
where 
city = coalesce(cty, city) and
country = coalesce(ctry, country) and
region = coalesce(reg, region)
limit 1;
4

1 回答 1

4

您的子句语法INTO不正确

假设您的查询本身是正确且功能正常的,并且您声明的lat变量lon更改了这部分

select latitude into lat, longitude into lon

SELECT latitude, longitude INTO  lat, lon

这是SQLFiddle演示

于 2013-08-26T00:56:28.863 回答