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我试图用 json 进行 ajax 调用，下面是我的代码描述

$(document).ajaxStart(function () {

    $("#innerpanel").html("<img class='test' src='Image/ajax-loader_clock.gif' alt='loading...' />");});

    /* $("#loader").ajaxStop(function () {
        $(this).hide();
    }); */

    $('#btn').click(function(){
        testService();
     });

    function  testService(){  
        name=$("#name").val();
        password=$("#password").val();
        var testData={name : name,password : password}; 

        $.ajax({
            type: "post",
            url: "login.do",
             data:testData,
             contentType: "application/json; charset=utf-8",
            dataType: "json", 
            success: function(msg) {
                alert("madhav");
                $("#innerpanel").html("<p1>Welcome</p1> </br>"+"<p1>"+msg.name+"</p1></br><p1> and Your password is "+msg.password+"</p1>");
                /* document.writeln("Book id: " +  msg.name); */
            }
        });
    }
});

服务器端代码是

String userName=request.getParameter("name");
String password=request.getParameter("password");
PrintWriter writer = response.getWriter();
JSONObject obj=new JSONObject();

obj.put("name", userName);
obj.put("password",password);
writer.print(obj);
writer.flush();

但是我的用户名和密码都为空值。请帮助我举例说明如何获取名称和密码服务器端。

如果我从请求中删除代码 

    contentType: "application/json; charset=utf-8",
    dataType: "json",

我使用上面的服务器端代码获取名称和密码值。但我怎么能不删除

    contentType: "application/json; charset=utf-8",
    dataType: "json",
4

1 回答 1

1 
var testData = {"name" : name, "password" : password};
于 2013-08-22T11:59:35.533 回答