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我正在创建记事本，现在当我尝试通过动态传递 id 并使用 Order by 来实现连接时遇到问题。它在“=”附近给出SQLiteexception。

我不知道我写这个查询的原因是什么：

String selectQuery = "SELECT " + KEY_TASKNOTE + " FROM " + TABLE_TODOTASK
            + " INNER JOIN" + TABLE_TODOTASK_DETAILS + "ON " + KEY_TASKID + "=" + KEY_TASK_DETAILS_TASKID + " WHERE " 
            + KEY_TASK_TASKLISTID + "=" + tasklist_Id + " ORDER BY " + KEY_TASK_DETAILS_DUEDATE;

常数：

// TASK table name
private static final String TABLE_TODOTASK = "todotask";
// TASKLIST Table Columns names
private static final String KEY_TASKID = "Id";
private static final String KEY_TASKNOTE = "tasknote";
private static final String KEY_TASKDUEDATE = "duedate";
private static final String KEY_TASKCOMPLETED = "taskcompleted";
private static final String KEY_TASK_TASKLISTID = "TaskList_id";

// TASKDETAILS table name
private static final String TABLE_TODOTASK_DETAILS = "todotaskdetails";
// TASKDETAILS Table Columns names
private static final String KEY_TASK_DETAILS_ID = "ID";
private static final String KEY_TASK_DETAILS_TASKID = "Task_id";
private static final String KEY_TASK_DETAILS_DUEDATE = "taskduedate";
private static final String KEY_TASK_DETAILS_EVENT = "taskevent";
private static final String KEY_TASKDETAILS_REMINDER = "taskreminder";
private static final String KEY_TASKDETAILS_REPEAT = "taskrepeat";
private static final String KEY_TASKDETAILS_PRIORITY = "taskpriority";

请帮忙，谢谢

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1 回答 1

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对于内部连接，您需要使用tablename1.fieldName = tablename2.fieldName，但您只使用了field name = field name. 像这样添加表前缀：

String selectQuery = "SELECT " + KEY_TASKNOTE + " FROM " + TABLE_TODOTASK
            + " INNER JOIN " + TABLE_TODOTASK_DETAILS + " ON " + TABLE_TODOTASK+"."+KEY_TASKID + "=" + TABLE_TODOTASK_DETAILS +"."+KEY_TASK_DETAILS_TASKID + " WHERE " 
            + KEY_TASK_TASKLISTID + "=" + tasklist_Id + " ORDER BY " + KEY_TASK_DETAILS_DUEDATE;

内连接的简单示例

SELECT column_name(s)
FROM table_name1
INNER JOIN table_name2 
ON table_name1.column_name=table_name2.column_name
于 2013-08-21T12:16:39.597 回答