android - 关于 SQLitedatabase 的语法错误，什么时候 select*from

Question

这是错误

android.database.sqlite.SQLiteException：靠近“FROMfriendsWHERE”：语法错误：，编译时：SELECT * FROMfriendsWHERE id！=？

这是我的代码

Cursor cursor = db.rawQuery("SELECT * FROM "+FriendsDBHelper.TABLE_NAME+" WHERE id != ?",new String[]{Integer.toString(0)});

Answer 1

尝试

Cursor cursor = db.rawQuery("SELECT * FROM "+FriendsDBHelper.TABLE_NAME+" WHERE id NOT LIKE ?",new String[]{Integer.toString(0)});

NOT LIKE是用来do not have ? value in it

或者

Cursor cursor = db.rawQuery("SELECT * FROM "+FriendsDBHelper.TABLE_NAME+" WHERE id <> ?",new String[]{Integer.toString(0)});

<>是用来is not equal to ?