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在 django 中，我在现有数据库中创建新模型。在同步模型时，它会显示错误。我无法解决这些问题。我正在使用 mysql 作为数据库。我添加了错误代码。请分享您的想法。

python manage.py syncdb
Creating tables ...
Creating table registration_securityquestions
Traceback (most recent call last):
  File "manage.py", line 14, in <module>
    execute_manager(settings)
  File "/usr/local/lib/python2.7/dist-packages/django/core/management/__init__.py", line 459, in execute_manager
    utility.execute()
  File "/usr/local/lib/python2.7/dist-packages/django/core/management/__init__.py", line 382, in execute
    self.fetch_command(subcommand).run_from_argv(self.argv)
  File "/usr/local/lib/python2.7/dist-packages/django/core/management/base.py", line 196, in run_from_argv
    self.execute(*args, **options.__dict__)
  File "/usr/local/lib/python2.7/dist-packages/django/core/management/base.py", line 232, in execute
    output = self.handle(*args, **options)
  File "/usr/local/lib/python2.7/dist-packages/django/core/management/base.py", line 371, in handle
    return self.handle_noargs(**options)
  File "/usr/local/lib/python2.7/dist-packages/django/core/management/commands/syncdb.py", line 102, in handle_noargs
    cursor.execute(statement)
  File "/usr/local/lib/python2.7/dist-packages/django/db/backends/util.py", line 40, in execute
    return self.cursor.execute(sql, params)
  File "/usr/local/lib/python2.7/dist-packages/django/db/backends/mysql/base.py", line 114, in execute
    return self.cursor.execute(query, args)
  File "/usr/lib/python2.7/dist-packages/MySQLdb/cursors.py", line 174, in execute
    self.errorhandler(self, exc, value)
  File "/usr/lib/python2.7/dist-packages/MySQLdb/connections.py", line 36, in defaulterrorhandler
    raise errorclass, errorvalue
django.db.utils.DatabaseError: (3, "Error writing file './userregdb/registration_securityquestions.frm' (Errcode: 28)")
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1 回答 1

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来自MySQL 文档：

上述错误是 Windows 的典型消息；Unix 消息类似。

一种解决方法是使用该--tmpdir选项启动 mysqld，或者将该选项添加到[mysqld]选项文件的部分。例如，要指定 的目录C:\temp，请使用以下行：

[mysqld]
tmpdir=C:/temp
于 2013-08-20T06:22:56.717 回答