1

更新数据后，当调用 web 服务时，它仍然会获取旧数据。仅当我注销应用程序然后再次登录时才会加载新数据。 

protected async override void OnNavigatedTo(System.Windows.Navigation.NavigationEventArgs e)
    {
            base.OnNavigatedTo(e);
            parameterValue = this.NavigationContext.QueryString["parameter"];

            Uri UserDetailUrl = new Uri(Constants.WebService.ws_single_user + "?user_id=" + parameterValue);
            HttpWebRequest UserDetailRequest = (HttpWebRequest)HttpWebRequest.Create(UserDetailUrl);
            HttpWebResponse UserDetailResponse = (HttpWebResponse)await UserDetailRequest.GetResponseAsync();
            StreamReader reader = new StreamReader(UserDetailResponse.GetResponseStream());
            string UserDetailString = reader.ReadToEnd();
            reader.Close();
            XDocument XUserDetailDoc = XDocument.Load(new StringReader(UserDetailString));
            if (((XElement)XUserDetailDoc.Element("main")).Element("result").Value == "success")
            {
                txtEmail.Text = ((XElement)XUserDetailDoc.Element("main")).Element("user").Element("email").Value;
                txtFirstName.Text = ((XElement)XUserDetailDoc.Element("main")).Element("user").Element("fname").Value;
                txtLastName.Text = ((XElement)XUserDetailDoc.Element("main")).Element("user").Element("lname").Value;
                txtMobile.Text = ((XElement)XUserDetailDoc.Element("main")).Element("user").Element("mobile").Value;
            }
    }

Windows 8 Phone 应用程序 - 使用 C# 和 XAML

GetResponseAsync 如下：

  public static Task<HttpWebResponse> GetResponseAsync(this HttpWebRequest request)
    {
        var taskComplete = new TaskCompletionSource<HttpWebResponse>();
        request.BeginGetResponse(asyncResponse =>
        {
            try
            {
                HttpWebRequest responseRequest = (HttpWebRequest)asyncResponse.AsyncState;
                HttpWebResponse someResponse = (HttpWebResponse)responseRequest.EndGetResponse(asyncResponse);
                taskComplete.TrySetResult(someResponse);
            }
            catch (WebException webExc)
            {
                HttpWebResponse failedResponse = (HttpWebResponse)webExc.Response;
                taskComplete.TrySetResult(failedResponse);
            }
        }, request);
        return taskComplete.Task;
4

3 回答 3

4

似乎HttpWebRequest正在返回缓存的结果。你有几种方法可以避免这种情况：

  1. 将随机字符串添加到 URL，因此每次访问不同的 URL（因此www.example.com/page变为www.example.com/page?random=dsa$fds21）。
  2. 禁用响应缓存，查看要添加的新代码OnNavigatedTo：

-

HttpWebRequest UserDetailRequest = (HttpWebRequest)HttpWebRequest.Create(UserDetailUrl); 
// Define a cache policy for this request only. 
HttpRequestCachePolicy noCachePolicy = new HttpRequestCachePolicy(HttpRequestCacheLevel.NoCacheNoStore);
request.CachePolicy = noCachePolicy;
于 2013-08-17T15:43:28.750 回答
2

我面临同样的问题，我通过在我的服务器端添加响应头来解决这个问题..

response.setHeader("Cache-Control", "no-cache");

可能这也会对您有所帮助。

于 2013-08-18T08:02:25.917 回答
0

如果您使用自己的 API，请尝试从那一侧关闭缓存。

于 2013-08-18T17:39:22.760 回答