objective-c - 在 Objective-C 中将 NSArray 转换为 NSString

Question

我想知道如何将NSArray转换为 Objective-C[@"Apple", @"Pear ", 323, @"Orange"]中的字符串。

Answer 1

NSString * result = [[array valueForKey:@"description"] componentsJoinedByString:@""];

Answer 2

一种方法是遍历数组，description在每个项目上调用消息：

NSMutableString * result = [[NSMutableString alloc] init];
for (NSObject * obj in array)
{
    [result appendString:[obj description]];
}
NSLog(@"The concatenated string is %@", result);

另一种方法是根据每个项目的类做一些事情：

NSMutableString * result = [[NSMutableString alloc] init];
for (NSObject * obj in array)
{
    if ([obj isKindOfClass:[NSNumber class]])
    {
        // append something
    }
    else
    {
        [result appendString:[obj description]];
    }
}
NSLog(@"The concatenated string is %@", result);

如果你想要逗号和其他无关信息，你可以这样做：

NSString * result = [array description];

Answer 3

I think Sanjay's answer was almost there but i used it this way

NSArray *myArray = [[NSArray alloc] initWithObjects:@"Hello",@"World", nil];
NSString *greeting = [myArray componentsJoinedByString:@" "];
NSLog(@"%@",greeting);

Output :

2015-01-25 08:47:14.830 StringTest[11639:394302] Hello World

As Sanjay had hinted - I used method componentsJoinedByString from NSArray that does joining and gives you back NSString

BTW NSString has reverse method componentsSeparatedByString that does the splitting and gives you NSArray back .

Answer 4

我最近发现了一个关于 Objective-C 字符串的非常好的教程：

http://ios-blog.co.uk/tutorials/objective-c-strings-a-guide-for-beginners/

我认为这可能很有趣：

如果要将字符串拆分为数组，请使用名为 componentsSeparatedByString 的方法来实现：

NSString *yourString = @"This is a test string";
    NSArray *yourWords = [myString componentsSeparatedByString:@" "];

    // yourWords is now: [@"This", @"is", @"a", @"test", @"string"]

如果你需要拆分一组不同的字符，使用 NSString 的 componentsSeparatedByCharactersInSet：

NSString *yourString = @"Foo-bar/iOS-Blog";
NSArray *yourWords = [myString componentsSeparatedByCharactersInSet:
                  [NSCharacterSet characterSetWithCharactersInString:@"-/"]
                ];

// yourWords is now: [@"Foo", @"bar", @"iOS", @"Blog"]

Note however that the separator string can’t be blank. If you need to separate a string into its individual characters, just loop through the length of the string and convert each char into a new string:

NSMutableArray *characters = [[NSMutableArray alloc] initWithCapacity:[myString length]];
for (int i=0; i < [myString length]; i++) {
    NSString *ichar  = [NSString stringWithFormat:@"%c", [myString characterAtIndex:i]];
    [characters addObject:ichar];
}

Answer 5

NSString * str = [componentsJoinedByString:@""];

and you have dic or multiple array then used bellow

NSString * result = [[array valueForKey:@"description"] componentsJoinedByString:@""];   

Answer 6

NSArray *array = [NSArray arrayWithObjects:@"One",@"Two",@"Three", nil];
NSString *stringFromArray = [array componentsJoinedByString:@" "];

The first line initializes an array with objects. The second line joins all elements of that array by adding the string inside the "" and returns a string.

Answer 7

Objective C Solution

NSArray * array = @[@"1", @"2", @"3"];
NSString * stringFromArray = [[array valueForKey:@"description"] componentsJoinedByString:@"-"];   // "1-2-3"

Those who are looking for a solution in Swift

If the array contains strings, you can use the String's join method:

var array = ["1", "2", "3"]

let stringFromArray = "-".join(array) // "1-2-3"

In Swift 2:

var array = ["1", "2", "3"]

let stringFromArray = array.joinWithSeparator("-") // "1-2-3"

In Swift 3 & 4

var array = ["1", "2", "3"]

let stringFromArray = array.joined(separator: "-") // "1-2-3"

Answer 8

The way I know is easy.

var NSArray_variable = NSArray_Object[n]
var stringVarible = NSArray_variable as String

n is the inner position in the array This in SWIFT Language. It might work in Objective C

Answer 9

Swift 3.0 solution:

let string = array.joined(separator: " ")