40

我试图以这种方式获取一个带有实际工作日名称的字符串：

            Calendar c = Calendar.getInstance();
            int dayOfWeek = c.get(Calendar.DAY_OF_WEEK);

            if (c.get(Calendar.MONDAY) == dayOfWeek) weekDay = "monday";
            else if (c.get(Calendar.TUESDAY) == dayOfWeek) weekDay = "tuesday";
            else if (c.get(Calendar.WEDNESDAY) == dayOfWeek) weekDay = "wednesday";
            else if (c.get(Calendar.THURSDAY) == dayOfWeek) weekDay = "thursday";
            else if (c.get(Calendar.FRIDAY) == dayOfWeek) weekDay = "friday";
            else if (c.get(Calendar.SATURDAY) == dayOfWeek) weekDay = "saturday";
            else if (c.get(Calendar.SUNDAY) == dayOfWeek) weekDay = "sunday";

但weekDay始终保持为空，我实际上不知道为什么，因为调试器说那dayOfWeek是 5 所以我应该等于c.get(Calendar.THURSDAY)

4

6 回答 6

84

就这么简单

sCalendar = Calendar.getInstance();
String dayLongName = sCalendar.getDisplayName(Calendar.DAY_OF_WEEK, Calendar.LONG, Locale.getDefault());
于 2014-04-24T10:58:12.090 回答
64

我通过执行以下操作来完成此操作：

String weekDay;
SimpleDateFormat dayFormat = new SimpleDateFormat("EEEE", Locale.getDefault());

Calendar calendar = Calendar.getInstance();
weekDay = dayFormat.format(calendar.getTime());
  • 使用“EEEE”的日期格式将返回完整的工作日名称，即星期二
  • 使用“E”的日期格式将返回缩写名称，即 Tue
  • 在 Android 中返回此格式的另一个好处是它将根据区域设置翻译工作日。

您将需要查看SimpleDateFormat以了解更多信息。我认为这是最简洁的方法，因为如果您只需要获取字符串值，则不需要switch或if语句。

于 2013-11-21T11:21:12.673 回答
17

您应该直接将 dayOfWeek 与 Calendar.MONDAY 等进行比较。请参见下面的代码

另外，我在 if else 周围加上了括号。不要依赖缩进来进行代码流，即使你的 if-else 只有一个语句，也要明确放置括号。

    public static void main(String[] args) {

    String weekDay = "";

    Calendar c = Calendar.getInstance();
    int dayOfWeek = c.get(Calendar.DAY_OF_WEEK);

    if (Calendar.MONDAY == dayOfWeek) {
        weekDay = "monday";
    } else if (Calendar.TUESDAY == dayOfWeek) {
        weekDay = "tuesday";
    } else if (Calendar.WEDNESDAY == dayOfWeek) {
        weekDay = "wednesday";
    } else if (Calendar.THURSDAY == dayOfWeek) {
        weekDay = "thursday";
    } else if (Calendar.FRIDAY == dayOfWeek) {
        weekDay = "friday";
    } else if (Calendar.SATURDAY == dayOfWeek) {
        weekDay = "saturday";
    } else if (Calendar.SUNDAY == dayOfWeek) {
        weekDay = "sunday";
    }

    System.out.println(weekDay);

}
于 2013-08-15T15:59:38.657 回答
3

没有必要使用c.get

    Calendar c = Calendar.getInstance();
    int dayOfWeek = c.get(Calendar.DAY_OF_WEEK);                

    if (Calendar.MONDAY == dayOfWeek) weekDay = "monday";
    else if (Calendar.TUESDAY == dayOfWeek) weekDay = "tuesday";
    else if (Calendar.WEDNESDAY == dayOfWeek) weekDay = "wednesday";
    else if (Calendar.THURSDAY == dayOfWeek) weekDay = "thursday";
    else if (Calendar.FRIDAY == dayOfWeek) weekDay = "friday";
    else if (Calendar.SATURDAY == dayOfWeek) weekDay = "saturday";
    else if (Calendar.SUNDAY == dayOfWeek) weekDay = "sunday";

    System.out.println(weekDay);

和输出：

thursday

如果您尝试c.get使用此代码打印值，您会看到错误

    System.out.println(c.get(Calendar.MONDAY));
    System.out.println(c.get(Calendar.TUESDAY));
    System.out.println(c.get(Calendar.WEDNESDAY));
    System.out.println(c.get(Calendar.THURSDAY));
    System.out.println(c.get(Calendar.FRIDAY));
    System.out.println(c.get(Calendar.SATURDAY));
    System.out.println(c.get(Calendar.SUNDAY));

例如我得到：

7
33
3
15
227
5
2013

结果将是不正确的，在我的情况下，我Sunday就像weekDay使用您的代码一样。

于 2013-08-15T16:01:33.310 回答
3

只需执行以下操作：

    Date date = new Date();
    CharSequence time = DateFormat.format("EEEE", date.getTime()); // gives like (Wednesday)
于 2014-10-22T09:04:39.880 回答
2

尝试这个 

import java.text.DateFormatSymbols;
import java.util.Date;
...
String[] weekdays = new DateFormatSymbols().getWeekdays();
String[] month = new DateFormatSymbols().getMonths();
System.outprintln(weekdays[date.getDay()+1]+","+month[date.getMonth()]+" "+date.getDate());
于 2013-10-14T16:47:21.703 回答