3

以下行返回空值：

List accountList = hibernateTemplate.find("from Accounts a where a.userId=?",userId);

我在控制台中得到以下信息：

2013-04-03 21:09:48 调试加载器：1197 - 结果行：空

2013-04-03 21:09:48 调试加载器：1197 - 结果行：空

这是我的实体类：

@Repository
@Entity
@Table(name = "ACCOUNTS")
public class Accounts {

    @Column(name="ACCOUNT_ID")
    @Id
    @GeneratedValue
    private int accountId;
    @Column(name="ACCOUNT_NUMBER")
    private String accountNumber;
    @Column(name="ACCOUNT_TYPE_CODE")
    private String accountTypeCode;
    @Column(name="USER_ID")
    private String userId;
    @Column(name="ACCOUNT_NAME")
    private String accountName;
    @Column(name="DATE_OPENED")
    private Date dateOpened;
    @Column(name="DATE_CLOSED")
    private Date dateClosed;
    @Column(name="CURRENT_BALANCE")
    private double currentBalance;
    @Column(name="OTHER_ACCOUNT_DETAILS")
    private String otherAccountDetails;
    @Column(name="ADD_TS")
    private Date addTimestamp;
    @Column(name="ADD_USR")
    private String addUser;
    @Column(name="UPDT_TS")
    private Date updateTimestamp;
    @Column(name="UPDT_USR")
    private String updateUser;
    
    @ManyToOne
    
    private Customer customer;

谁能帮我解决这个问题？我真的很感激。

这是 Hibernate 生成的查询

Hibernate: select accounts0_.ACCOUNT_ID as ACCOUNT1_23_, accounts0_.ACCOUNT_NAME as ACCOUNT2_23_, accounts0_.ACCOUNT_NUMBER as ACCOUNT3_23_, accounts0_.ACCOUNT_TYPE_CODE as ACCOUNT4_23_, accounts0_.ADD_TS as ADD5_23_, accounts0_.ADD_USR as ADD6_23_, accounts0_.CURRENT_BALANCE as CURRENT7_23_, accounts0_.customer_CUSTOMER_ID as customer14_23_ ，account0_.DATE_CLOSED 作为 DATE8_23_，accounts0_.DATE_OPENED 作为 DATE9_23_，accounts0_.OTHER_ACCOUNT_DETAILS 作为 OTHER10_23_，accounts0_.UPDT_TS 作为 UPDT11_23_，accounts0_.UPDT_USR 作为 UPDT12_23_，account0_.USER_ID 作为 USER13_23_ 从 ACCOUNT_ID=？

查询有问题吗？或域配置？

请帮我。

4

1 回答 1

0

我有点不明白为什么要设置 USER_ID String(varchar) 类型的列，但是关于你的情况，你可以这样写：

hibernateTemplate.find("from Accounts a where a.userId='" + userId + "'");

它会很好用，也许对你有帮助:)

于 2013-04-04T12:24:27.323 回答