1

请帮我解决这个问题。当第 2 列以第 1 列相同的方式获得结果时，我得到空值。

select 
   (case when parents  = '3' then child end) 3_rec,
   (case when parents  = '10' then child end) 10_rec
from
(
  SELECT concat(a.name,' (',b.count,')') as child,b.parent as parents FROM wp_terms a,wp_term_taxonomy b where 
a.term_id=b.term_id and b.parent = 3 and b.taxonomy = 'category'
  union all
  SELECT concat(a.name,' (',b.count,')') as child,b.parent as parents FROM wp_terms a,wp_term_taxonomy b where 
a.term_id=b.term_id and b.parent = 10 and b.taxonomy = 'category'
) d order by 1,2 asc

我期待的结果。Null 应该排在最后。

3_rec|10_rec
------------
row1 | row1
row2 | row2
row3 | row3
     | row4
     | row5
4

1 回答 1

3

你对做什么有很大的误解union all。您的select声明：

select (case when parents  = '3' then child end) 3_rec,
      (case when parents  = '10' then child end) 10_rec

总是会NULL在至少一列中返回。

您似乎想要对齐列。首先，我会问以下查询是否足以满足您的需求：

  SELECT concat(a.name,' (',b.count,')') as child,b.parent as parents
  FROM wp_terms a join
       wp_term_taxonomy b 
       on a.term_id=b.term_id
  WHERE b.parent in (3, 10) and b.taxonomy = 'category'

这将返回不同行上的值。或者，您可以这样做：

  SELECT b.parent,
         group_concat(concat(a.name,' (',b.count,')'), ';') as children
  FROM wp_terms a join
       wp_term_taxonomy b 
       on a.term_id=b.term_id
  WHERE b.parent in (3, 10) and b.taxonomy = 'category'
  group by p.parent;

在两列中对齐列表不是 SQL 的强项（可能，但不容易）。因此，如果有其他解决方案，那就去做吧。

编辑：

为了得到你想要的，你需要两个列表的行号。而且你没有，所以你必须用一个变量创建一个。

select max(case when parent = 3 then child end) as "3_child",
       max(case when parent = 10 then child end) as "10_child"
from (SELECT concat(a.name,' (',b.count,')') as child, b.parent as parents,
             @rn := if(@parent = b.parent, @rn + 1, 1) as rn,
             @parent := b.parent
      FROM wp_terms a join
           wp_term_taxonomy b 
           on a.term_id=b.term_id cross join
           (select @rn := 0, @parent := '') const
      WHERE b.parent in (3, 10) and b.taxonomy = 'category'
      order by b.parent
     ) t
group by rn
order by rn;
于 2013-08-15T11:03:12.193 回答