iphone - 自定义导航栏上的后退按钮

Question

我正在尝试开发一个带有自定义大小导航栏的应用程序。(100px) 在导航栏中，我还想包含一个后退按钮。我已经使用子视图添加了它们，但是后退按钮不起作用：

UIButton *backBtn = [UIButton buttonWithType:UIButtonTypeCustom];
UIImage *backBtnImage = [UIImage imageNamed:@"menueButton.png"];
UIImage *backBtnImagePressed = [UIImage imageNamed:@"menueButton.png"];

backBtn.exclusiveTouch = YES;
[backBtn addTarget:self action:@selector(back:) forControlEvents:UIControlEventTouchUpInside];
[backBtn setBackgroundImage:backBtnImage forState:UIControlStateNormal];
[backBtn setBackgroundImage:backBtnImagePressed forState:UIControlStateHighlighted];


backBtn.frame = CGRectMake(0, -40, 35, 32);
UIView *backButtonView = [[UIView alloc] initWithFrame:CGRectMake(0, -40, 35 , 32)];
[backButtonView addSubview:backBtn];
UIBarButtonItem *backButton = [[UIBarButtonItem alloc] initWithCustomView:backButtonView];
self.navigationItem.leftBarButtonItem = backButton;

我的导航栏大小为 100 像素高，当我使用按钮位置 (0,0,35,32) 时，它会正常工作。但是在这种情况下，按钮的显示比预期的要低得多。我究竟做错了什么？

Answer 1

尝试像这样分配 backButtonView

UIView *backButtonView = [[UIView alloc] initWithFrame:CGRectMake(0, 0, 35 , 32)];

更改：视图原点为 (0,0)

编辑

尝试

backBtn.frame = CGRectMake(0, 0, 35, 32);
UIView *backButtonView = [[UIView alloc] initWithFrame:CGRectMake(0, -40, 35 , 32)];

Answer 2

self.btnBack = [UIButton buttonWithType:UIButtonTypeCustom];
[self.btnBack setImage:[UIImage imageNamed:@"back_active.png"] forState:UIControlStateNormal];
[self.btnBack addTarget:self action:@selector(back) forControlEvents:UIControlEventTouchUpInside];
self.btnBack.frame = CGRectMake(5, 9, 50, 30);
[self.navigationController.navigationBar addSubview:self.btnBack];

也检查这个链接。

更新：后退按钮

-(void)back
{

[self.btnBack removeFromSuperview];
[self.navigationController popViewControllerAnimated animated:NO];
}