0

我有一门课有 4 分的考试成绩。测试 1 - 测试 4。我想创建一个名为 mean 的函数,它将计算课程中每次考试的平均值并将其存储在 mean 数组中。但我似乎无法通过一个循环来完成这个:

class Cstudent
{
public:
    string firstName, lastName;
    int test1, test2, test3, test4;
    float average;
};

/* Here is the problem, the next time i go through the loop, i want to store the sum of
test2 in to sum[1] after already storing the total in to sum[0] for test 1 */

float mean(Cstudent section[], int n)
{
    int sum[NUMBEROFEXAMS];
    float mean[NUMBEROFEXAMS];
    for(int i = 0; i < NUMBEROFEXAMS; i++)
        for(int j = 0; j < n; j++){
            sum[i] += section[j].test1;
        }

}
4

2 回答 2

2

将分数存储在数组中会更容易:

#include <array>

class Student
{
public:
    string firstName, lastName;
    std::array<int, 4> test;
    float average;
};

然后你可以很容易地得到平均值:

#include <algorithm> // for std::accumulate

Student s = ....;
...
float avg = std::accumulate(s.test.begin(), s.test.end(), 1.0)/s.test.size();
于 2013-08-11T15:40:06.567 回答
1

你是说这个吗:

float mean(Cstudent section[], int n)
{
    int sum[NUMBEROFEXAMS];
    float mean[NUMBEROFEXAMS];
    for(int i = 0; i < NUMBEROFEXAMS; i+=4)
        for(int j = 0; j < n; j++){
            sum[i] += section[j].test1;
            sum[i+1] += section[j].test2;
            sum[i+2] += section[j].test3;
            sum[i+3] += section[j].test4;
        }

}
于 2013-08-11T15:47:45.553 回答