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最近在玩《塞尔达传说》季节神谕和时代神谕游戏，密码引起了我的注意。我现在想用 Python 或 Java 重新创建它，看看它是如何工作的。

问题是，我找不到办法。你将如何制作一个编码系统

  1. 依赖于您输入的第一个“链接”代码（迷宫或全息镜的秘密，因为它在游戏中被命名），因此您不能从其他人那里窃取代码；
  2. 检测错别字。如果你输入 fobaz 而不是 foobar，它会检测到代码错误；
  3. 可以存储一堆（相当数量）的信息。它也介于 5-20 个字符之间，就像在游戏中一样（这不是必需的，但会很好）

注意：我不是要为 Oracle 游戏创建生成器，只是一些代码来生成和读取类似于 Oracle 游戏中的秘密

这个问题的编程范围是如何使用模仿 Oracle 游戏中的密码的系统对信息进行编码和解码。

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1 回答 1

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我希望这是一种序列化+编码的形式。

您基本上需要生成一个包含各种秘密值的字节数组（这是大多数二进制协议的编写方式），然后将每个字节编码为相应的字符（或更多），以便输出“字符串”可读。下面是如何在 Python 中将数据序列化为字节数组的示例：

玩家信息

player_name = "Robert"

player_stats = {
    "health": 200,
    "mana": 150,
    "has_sword": True,
    "has_arrows": False,
    "has_shovel": True,
    "dungeon1_complete": True
}

设置序列化信息

# If these can be greater than 255, they must be stored across multiple bytes - extra work
byte_attribs = ["health", "mana"]

bit_attribs = ["has_sword", "has_arrows", "has_shovel", "dungeon1_complete"]

player_name_max_length = 7
byte_attrib_offset = player_name_max_length
bit_attrib_offset = byte_attrib_offset + len(byte_attribs)

secret_storage = bytearray(bit_attrib_offset + len(bit_attribs))

assert(len(player_name) <= player_name_max_length)

执行序列化

# Serialize Player Name
secret_storage[:player_name_max_length] = player_name.rjust(player_name_max_length)

# Serialize attributes:
for idx, attrib in enumerate(byte_attribs):
    secret_storage[byte_attrib_offset + idx] = player_stats[attrib]

for idx, attrib in enumerate(bit_attribs):
    byte_offset = idx // 8  # attribs 0-7 go in byte 0, etc.
    bit_offset = idx % 8

    # Bit manipulation examples: http://wiki.python.org/moin/BitManipulation
    current_byte = bit_attrib_offset + byte_offset
    if player_stats[attrib]:
        mask = 1 << bit_offset
        secret_storage[current_byte] = secret_storage[current_byte] | mask
    else:
        mask = ~(1 << bit_offset)
        secret_storage[current_byte] = secret_storage[current_byte] & mask

检索单个值

print "Storage array encoded as ascii:", secret_storage

# Access name:
print "Name:", secret_storage[:player_name_max_length].lstrip()
# >>> Name: Robert

# Access byte values:
attrib_idx = byte_attribs.index("mana")
print "Mana level:", secret_storage[byte_attrib_offset + attrib_idx]
# >>> Mana level: 150

# Access bit flags:
attrib_idx = bit_attribs.index("dungeon1_complete")
print "Completed Dungeon 1:", bool(secret_storage[bit_attrib_offset + (attrib_idx // 8)] & (1 << attrib_idx % 8))
# >>> Completed Dungeon 1: True
于 2013-08-11T01:07:44.890 回答