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正如你所看到的，我一直在修改和修改我在各处找到的代码片段，这需要很长时间！

I'm stuck on the context menu which isn't capturing the touch selection when an item is selected, and eclipse is showing an error which I'm not sure how to correct.

我不确定如何在主线程中引用数组列表，如果它是来自字符串的数组，我知道该怎么做，但不是在主线程上。

带*的行是给出错误的行。

只是想知道是否有人可以偷看它？

import java.util.ArrayList;
import android.app.ListActivity;
import android.media.MediaPlayer;
import android.os.Bundle;
import android.view.ContextMenu;
import android.view.ContextMenu.ContextMenuInfo;
import android.view.MenuInflater;
import android.view.MenuItem;
import android.view.View;
import android.widget.AdapterView.AdapterContextMenuInfo;
import android.widget.ListView;
import android.widget.Toast;
public class MainActivity extends ListActivity {
private ArrayList<Sound> mSounds = null;
private SoundAdapter mAdapter = null;
static MediaPlayer mMediaPlayer = null;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
registerForContextMenu(getListView());
this.getListView().setSelector(R.drawable.selector);
mSounds = new ArrayList<Sound>();
mSounds.add(s);
s = new Sound();
s.setDescription("Echoex");
s.setSoundResourceId(R.raw.echoex);
mSounds.add(s);
s = new Sound();
s.setDescription("Edge");
s.setSoundResourceId(R.raw.edge);
mSounds.add(s);
s = new Sound();
s.setDescription("Enterprise");
s.setSoundResourceId(R.raw.enterprise);
mSounds.add(s);
s = new Sound();
s.setDescription("Envy");
s.setSoundResourceId(R.raw.envy);
mSounds.add(s);
s = new Sound();
s.setDescription("Etcher");
s.setSoundResourceId(R.raw.etcher);
mSounds.add(s);
mAdapter = new SoundAdapter(this, R.layout.list_row, mSounds);
setListAdapter(mAdapter);
}
@Override
public void onListItemClick(ListView parent, View v, int position, long id){
Sound s = (Sound) mSounds.get(position);
MediaPlayer mp = MediaPlayer.create(this, s.getSoundResourceId());
mp.start();

}@Override
public void onCreateContextMenu(ContextMenu menu, View v, ContextMenuInfo menuInfo) {
    super.onCreateContextMenu(menu, v, menuInfo);
    MenuInflater inflater = getMenuInflater();
    inflater.inflate(R.menu.context_menu, menu);
  }
@Override
public boolean onContextItemSelected(MenuItem item) {
    AdapterContextMenuInfo info = (AdapterContextMenuInfo) item.getMenuInfo();
    ********String[] names = getResources().getString(R.array.mSounds);
    switch(item.getItemId()) {
    case R.id.setasnotification:
          Toast.makeText(this, "Applying " + getResources().getString(R.string.setas) +
                      " context menu option for " + names[(int)info.id],
                      Toast.LENGTH_SHORT).show();
          return true;
    default:
          return super.onContextItemSelected(item);
    }
}}

声音.java：

public class Sound {
private String mDescription = "";
private int mSoundResourceId = -1;
private int mIconResourceId = -1;
public void setDescription(String description) { mDescription = description; }
public String getDescription() { return mDescription; }
public void setSoundResourceId(int id) { mSoundResourceId = id; }
public int getSoundResourceId() { return mSoundResourceId; }
public void setIconResourceId(int id) { mIconResourceId = id; }
public int getIconResourceId() { return mIconResourceId; }
}
4

3 回答 3

1

你必须使用

String[] names = getResources().getStringArray(R.array.names);

代替

********String[] names = getResources().getString(R.array.names);
于 2013-08-10T08:44:40.920 回答
0

您的目标参数可能不正确。

********String[] names = getResources().getString(R.array.mSounds);

我有一种感觉，你的目标是 mSound，ArrayList<Sound>类型。这种方法用这种方式行不通。如果您想使用上述方法，您必须创建一个 XML 文件。下面是一个例子，

<?xml version="1.0" encoding="utf-8"?>  
<resources>  
    <array name="myArray">  
        <item>first song</item>  
        <item>second song</item>  
        <item>third song</item>  
        <item>fourth song</item>  
        <item>fifth song</item>  
    </array>
</resources>

这将保存到soundArray.xml下面的 XML 文件中。然后你可以使用上面的方法作为

String[] names = getResources().getStringArray(R.array.soundArray);

这应该有效。

或者，如果您想使用 Sound 对象

（这不是一个 android 类？）您必须遍历列表并返回所述声音对象的字符串。

int length = mSounds.size(); // get the length of mSounds object
String[] names = new String[length]; // creates a fixed array with strings
for(int i = 0; i < length; i++) {
     // add sound name to string array
     names[i] = mSounds.get(i).getDescription(); // returns the string name
}

但是，如果Sound该类是您的自定义类，您必须查看它是否包含返回所述声音项名称的方法。如果没有（或者如果您没有覆盖 toString() 方法，它将返回参考地址，这是您不想看到的东西......

于 2013-08-10T09:17:16.113 回答
0

改变

 ********String[] names = getResources().getString(R.array.names);

至

 String[] names = getResources().getString(R.array.names);

您还可以在ArrayList mSound不实例化的情况下添加对象mSound。你应该这样做：

@Override
public void onCreate(Bundle savedInstanceState) {

.....

    mSound = new ArrayList<Sound>();

然后做

   mSound.add(s);

}
于 2013-08-10T08:49:58.473 回答