python - 使用 Python 属性访问链接访问字典获取字符串

Question

我目前得到这样的输出：

http://www.site.com/prof.php?pID=478http://www.site.com/prof.php?pID=693

在使用下面评论者的建议后，我有：

urls = [el.url for el in domainLinkOutput]
return HttpResponse(urls)

如何将此输出转换为 python 字典，例如：

urls = { '0': 'http://www.site.com/prof.php?pID=478', '1': 'http://www.site.com/prof.php?pID=693' }

Answer 1

I don't believe you need regex here - just use attribute access on the Link objects you have...

If you have a list of Link objects, then use something like:

urls = [el.url for el in list_of_objects]

You should just be able to get the url by Link_object.url...

Answer 2

使用此正则表达式匹配 url：

url='([^']+)'

样本输出：

    [0] => http://www.somesite.com/prof.php?pID=478
    [1] => http://www.somesite.com/prof.php?pID=527
    [2] => http://www.somesite.com/prof.php?pID=645

如果要排除参数，请使用

url='([^'?]+)

样本输出：

    [0] => http://www.somesite.com/prof.php
    [1] => http://www.somesite.com/prof.php
    [2] => http://www.somesite.com/prof.php

Answer 3

你可以试试re.finditer。

r = re.compile("url='(.*?)'")
for match in r.finditer(input):
    print match.group[1]

您可以在此处阅读 Python 文档。