1

我有一些来自我在表格上发布的数据库的数据。对于表的每一行（while 循环的每个循环），我需要调用一个存储过程来计算<td>我的表的最后一个数据。

这里有一些代码：

$s = $lk->query("SELECT *
                  FROM A_USERS
                  JOIN A_DATA
                  WHERE A_DATA.id_user = A_USERS.id
                    AND A_USERS.usr_att = 1
                    AND A_DATA.act_data = 1
                    AND A_DATA.a_att = 1
                    AND A_DATA.qty IS NOT NULL
                  ORDER BY ID ASC");


while ($dato = $s->fetch_object()) {
    print '<tr>';

    print '<td>';   
    print $dato->id;
    print '</td>';

    //others cells


    $GetP = $lk->query("CALL GetPr($dato->qty, '$dato->prod')");

    if(mysqli_num_rows($GetP) === 1){
        while($p_db = mysqli_fetch_array($GetP)){
            $p = $p_db['p'];
        }

        $format = number_format(round($p, 1), 2, ',', '\'');

        //some other stuff here...

    }else{
        print '<td>';
        print 'ERROR';
        print '</td>';
    }
    print '</tr>';
}

问题是只有第一个循环while调用返回的过程1 row。否则我总是ERROR在这<td>意味着存储过程没有返回1 row。

为什么？

编辑

存储过程：

CREATE DEFINER=`...` PROCEDURE `GetPr`(IN `cli_qty` INT, IN `cli_prod` VARCHAR(10) CHARSET ascii)
BEGIN
    SET @cli_qty = cli_qty;

    SET @q = (SELECT qty FROM MRG_H ORDER BY ABS(@cli_qty - qty) ASC LIMIT 1);

    SET @cli_prod = cli_prod;

    IF @cli_prod = 'OECO' THEN SET @marg = (SELECT (m+v) FROM MRG_H JOIN DT WHERE m <> '' AND q = @q AND par = 'MarOECO');

    ELSE SET @marg = (SELECT m FROM MRG_H WHERE m <> '' AND q = @q);
    END IF;

    SELECT (Med+@marg)*((Val+100)/100) AS P, D_aaaammgg AS Date
        FROM PL
          JOIN TVA
        WHERE I_D = 0
      AND Med <> ''
      AND Date_f = ''
        ORDER BY Iden DESC
        LIMIT 1;
END

MYSQLI 错误：

Error: 2014-Commands out of sync; you can't run this command now
4

2 回答 2

2

在@Mihai 的建议下，我找到了这个解决方案：

参考：PHP手册

while ($dato = $s->fetch_object()) {
    print '<tr>';

    print '<td>';   
    print $dato->id;
    print '</td>';

    //others cells


    $GetP = $lk->query("CALL GetPr($dato->qty, '$dato->prod')");

    if(mysqli_num_rows($GetP) === 1){
        while($p_db = mysqli_fetch_array($GetP)){
            $p = $p_db['p'];
        }

        $format = number_format(round($p, 1), 2, ',', '\'');

        //some other stuff here...

    }else{
        print '<td>';
        print 'ERROR';
        print '</td>';
    }

    //Added this 2 lines
    $GetPrice->close();
    $link->next_result();

    print '</tr>';
}
于 2013-08-09T12:16:37.637 回答
2

不确定这是问题所在，但 mysqli_fetch_array 推进了内部指针，将其替换为 mysqli_num_rows。

while($p_db = mysqli_fetch_array($GetP)){
        $p = $p_db['p'];
    }

编辑：

http://www.php.net/manual/en/mysqli.query.php#102904

$s->close();

$lk->next_result();

把这个2放在//其他单元格下。

而且，用 fetch_all 替换 fetch_object。

于 2013-08-09T11:31:10.253 回答