sql-server - 如果多行具有相同的 Name 值，则返回 ID 值最高的行

Question

ID  Name    Address Birthdate

1   Steven  NULL    1982-01-23 

2   Andrew  2 Katherine St  1979-10-06

3   Andrew  81 South Rd NULL

在上表中，如果我在文本框中输入 Andrew，我想获取 Id no=3 的数据。怎么做到呢？

Answer 1

对于所有唯一名称：

;WITH cte AS
(
  SELECT ID, Name, Address, Birthdate,
    rn = ROW_NUMBER() OVER (PARTITION BY Name ORDER BY ID DESC)
  FROM dbo.tablename
)
SELECT ID, Name, Address, Birthdate
FROM cte
WHERE rn = 1;

只为一个：

SELECT TOP (1) ID, Name, Address, Birthdate
  FROM dbo.tablename
  WHERE Name = 'Andrew'
  ORDER BY ID DESC;

Answer 2

declare @name varchar(100) = 'Andrew'

select top 1 *
from MyTable
where Name = @name
order by ID desc

Answer 3

假设表名是“my_table”。尝试这个：

SELECT max(ID) FROM my_table WHERE Name = 'Andrew'

更多关于这里的 max 函数。