5

我有以下代码，其中删除了凭据的初始化。目录列表的打印工作，但是“获取”失败，出现以下异常

在我看来，预取失败了，因为我在 getfo 中提取了代码并让它在我的代码中作为一个函数工作，并且预取被注释掉了。

有更好的解决方案吗？

*** Caught exception: <type 'exceptions.IOError'>: [Errno 2] The message [/Inbox/CD.BAIINT.D130802.T200541.M856559] is not extractable!
Traceback (most recent call last):
  File "C:\Projects\Python\SFTP\SFTPHSC.py", line 71, in <module>
    sftp.get(files, localpath + "/" + files)
  File "build\bdist.win-amd64\egg\paramiko\sftp_client.py", line 676, in get
    size = self.getfo(remotepath, fl, callback)
  File "build\bdist.win-amd64\egg\paramiko\sftp_client.py", line 640, in getfo
    file_size = self.stat(remotepath).st_size
  File "build\bdist.win-amd64\egg\paramiko\sftp_client.py", line 337, in stat
    t, msg = self._request(CMD_STAT, path)
  File "build\bdist.win-amd64\egg\paramiko\sftp_client.py", line 689, in _request
    return self._read_response(num)
  File "build\bdist.win-amd64\egg\paramiko\sftp_client.py", line 736, in _read_response
    self._convert_status(msg)
  File "build\bdist.win-amd64\egg\paramiko\sftp_client.py", line 762, in _convert_status
    raise IOError(errno.ENOENT, text)
IOError: [Errno 2] The message [/Inbox/CD.BAIINT.D130802.T200541.M856559] is not extractable!

username = ''
password=''
hostname =''
port=22
localpath ="c:/BkFiles/"
t = paramiko.Transport((hostname, port))

try:
    t.connect(username=username, password=password)
    sftp = paramiko.SFTPClient.from_transport(t)

    dirlist = sftp.listdir('.')
    print "Dirlist:", dirlist

    sftp.chdir('Inbox')
    dirlist = sftp.listdir('.')
    print "Dirlist:", dirlist

    for files in dirlist:
        sftp.get(files, localpath + files)
        print files
except Exception, e:
    print '*** Caught exception: %s: %s' % (e.__class__, e)
    traceback.print_exc()
finally:
     try:
        t.close()
     except:
        pass
4

1 回答 1

3

您可以在回溯中找到您遇到的具体错误。查看 Paramiko 的sftp_client.py:760的源代码：

elif code == SFTP_NO_SUCH_FILE:
    raise IOError(errno.ENOENT, text)

1）显然，您正在尝试 sftp GET 一个根本不存在的文件，或者将其保存到本地计算机上不存在的路径中。尝试修改您的代码以打印出您正在下载的路径以及将其保存到的位置：

for files in dirlist:
    print ' -> Attempting to download: "{}", and saving it {}'.format(files, localpath + files)
    sftp.get(files, localpath + files)
print files

2）您可以缩短sftp.listdir('.')到，sftp.listdir()因为路径的默认参数已经是'.'.

3) 您甚至可能希望打印出目标文件的统计信息以进行进一步调试：

for files in dirlist:
    print ' -> Attempting to download: "{}", and saving it {}'.format(files, localpath + files)
    print ' --> remotepath stat: {}'.format(sftp.stat(files))
    sftp.get(files, localpath + files)
    print files
于 2013-10-31T23:26:32.483 回答