iphone - ios中的十进制值四舍五入到下一个更高的值

Question

在我的应用程序中，我接受金额值（浮动）并保存它。在金额字段中，用户可以输入小数点后的任意位数。但是当我阅读并保存时，它应该只有小数点后两位数。这种情况适用于我的代码。但问题是，如果用户输入值 2.468，它会被保存为 2.47。但如果用户输入是 2.245，在这种情况下，我需要保存为 2.25，但它只保存为 2.24。

我的代码是

AmountValue = [NSString stringWithFormat:@"%f",[AmountTxt1.text floatValue]];
 float Rate_int = [AmountValue floatValue];

NSNumberFormatter *currencyFormatter = [[NSNumberFormatter alloc] init];
[currencyFormatter setNumberStyle:NSNumberFormatterCurrencyStyle];
NSString *str1 = [NSString stringWithFormat:@"%@",[currencyFormatter stringFromNumber:[NSNumber numberWithFloat:Rate_int]]];

TotalAmtTxt.text = str1;

Answer 1

float a=2.245;
float b=ceilf(a*100)/100; 

或者

NSNumberFormatter *currencyFormatter = [[NSNumberFormatter alloc] init];
    [currencyFormatter setNumberStyle:NSNumberFormatterDecimalStyle];
    [currencyFormatter setRoundingMode:NSNumberFormatterRoundCeiling];
    [currencyFormatter setMaximumFractionDigits:2];

Answer 2

double Rate_int1 = [input doubleValue];

NSNumberFormatter *formatter = [[NSNumberFormatter alloc] init];
[formatter setNumberStyle:NSNumberFormatterDecimalStyle];
[formatter setRoundingMode: NSNumberFormatterRoundHalfUp];
[formatter setMaximumFractionDigits:2];

NSString *numberString = [formatter stringFromNumber:[NSNumber numberWithDouble:Rate_int1]];

NSString numberString 具有四舍五入的值..

Answer 3

您添加此代码：

[currencyFormatter setNumberStyle:NSNumberFormatterDecimalStyle];
[currencyFormatter setRoundingMode:NSNumberFormatterRoundHalfUp];
[currencyFormatter setMaximumFractionDigits:2];

NSLog(@"%@",[currencyFormatter stringFromNumber:[NSNumber numberWithDouble:2.245]]);

Answer 4

试试这个代码..

 NSNumberFormatter *formatter = [[NSNumberFormatter alloc] init];
 [formatter setNumberStyle:NSNumberFormatterDecimalStyle];
 [formatter setMaximumFractionDigits:2];
 [formatter setRoundingMode: NSNumberFormatterRoundHalfUp];

 NSString *numberString = [formatter stringFromNumber:[NSNumber numberWithFloat:Rate_int]];

 TotalAmt.txt = numberString;