所以这是我所有的代码,我真的不明白为什么会出现这些错误。问题出在导出配方功能中。
#include<iostream>
#include<fstream>
#include<map>
#include<vector>
#include<string>
using namespace std;
void DisplayMenu();
void AddRecipe( map< string, vector<string> >& recipes );
void ExportRecipes( map< string, vector<string> >& recipes );
int main ( void ){
int choice = 0;
bool done = false;
map< string, vector<string> > recipes;
while ( done == false ){
DisplayMenu();
cin >> choice;
if ( choice == 3 ){
done = true;
}
else if ( choice == 2 ){
ExportRecipes( recipes );
}
else if ( choice == 1 ){
AddRecipe( recipes );
}
}
}
void DisplayMenu(){
cout << "1. Add Recipe " << endl;
cout << "2. Export Recipes " << endl;
cout << "3. Exit" << endl;
}
void AddRecipe( map< string, vector<string> >& recipes ){
string name, ingredient;
bool done = false;
cout << "Enter recipe name: ";
cin >> name;
while ( done == false ){
cout << "Enter new ingredient and amount( enter done to exit )" << endl;
getline( cin , ingredient, '\n' );
if ( ingredient == "done" ){
done = true;
}
if( ingredient != "done"){
recipes[ name ].push_back( ingredient );
cout << "Added \"" << ingredient << "\"." << endl << endl;
}
}
}
void ExportRecipes( map< string, vector<string> >&recipes ){
ofstream outFile;
outFile.open( "Recipes.txt" );
for ( map< string, vector<string> >::iterator recipe =
recipes.begin(); recipe != recipes.end(); recipe++ ) {
outFile << endl << endl << recipe -> first << endl;
for ( map< string, vector<string> >::iterator ingredients =
recipe->second.begin(); ingredients != recipe->second.end();
ingredients++ ) {
outFile << "\t" << *ingredients << endl;
}
}
}
如果我只遍历导出中的第一个 for 循环,我可以获得密钥,但我根本无法获得值。