regex - how to get value of url parameter with colon in text in django

Question

I have the following url:

http://mysite.com/config/1:1/

This gives me a 404 page not found.

If I try this: it find my url entry no problem. http://mysite.com/config/1/

This what my url pattern looks like:

 url(r'^config/(?P<config_id>\d+)/$', views.config, name='config'),

Is there a problem with having the colon in the url?

Answer 1

您的正则表达式只允许数字。 \d不匹配:。如果您的视图函数能够处理冒号，请扩大模式：

url(r'^config/(?P<config_id>[\d:]+)/$', views.config, name='config')

由于您已经命名了模式config_id，我怀疑它是主键，这不适用于视图，但这取决于视图本身。