javascript - Javascript将函数设置为带参数的函数

Question

我正在尝试将对象的“触摸”功能设置为另一个功能。我一直听说 JavaScript 和一流的函数，但仍然没有掌握它的窍门。这是我所拥有的：

customClose.touched = this._close.bind(this);

customClose 有一个名为“touched”的函数，默认为空。我希望将它设置为另一个函数 this._close.bind，它接受一个参数。我怎样才能使这项工作？

Answer 1

It turns out my original implementation was correct. The problem was that the close button had moved due to another change I had made. Since it's invisible, I didn't notice. Binding the function to the object's function is done as follows:

customClose.touched = this._close.bind;

Answer 2

这可以解决问题：

customClose.touched = this._close.bind;

注意，如果你使用thisinside of this._close.bind，在调用的时候customClose.touched(p)，this会引用customClose.

如果要this继续引用this._close，可以使用bind：

customClose.touched = this._close.bind.bind(this._close);