93

似乎很容易获得

From
To
Subject

等通过

import email
b = email.message_from_string(a)
bbb = b['from']
ccc = b['to']

假设这"a"是看起来像这样的原始电子邮件字符串。

a = """From root@a1.local.tld Thu Jul 25 19:28:59 2013
Received: from a1.local.tld (localhost [127.0.0.1])
    by a1.local.tld (8.14.4/8.14.4) with ESMTP id r6Q2SxeQ003866
    for <ooo@a1.local.tld>; Thu, 25 Jul 2013 19:28:59 -0700
Received: (from root@localhost)
    by a1.local.tld (8.14.4/8.14.4/Submit) id r6Q2Sxbh003865;
    Thu, 25 Jul 2013 19:28:59 -0700
From: root@a1.local.tld
Subject: oooooooooooooooo
To: ooo@a1.local.tld
Cc: 
X-Originating-IP: 192.168.15.127
X-Mailer: Webmin 1.420
Message-Id: <1374805739.3861@a1>
Date: Thu, 25 Jul 2013 19:28:59 -0700 (PDT)
MIME-Version: 1.0
Content-Type: multipart/mixed; boundary="bound1374805739"

This is a multi-part message in MIME format.

--bound1374805739
Content-Type: text/plain
Content-Transfer-Encoding: 7bit

ooooooooooooooooooooooooooooooooooooooooooooooo
ooooooooooooooooooooooooooooooooooooooooooooooo
ooooooooooooooooooooooooooooooooooooooooooooooo

--bound1374805739--"""

问题

你如何Body通过 python 获得这封电子邮件？

到目前为止，这是我知道的唯一代码，但我还没有测试它。

if email.is_multipart():
    for part in email.get_payload():
        print part.get_payload()
else:
    print email.get_payload()

这是正确的方法吗？

或者也许有一些更简单的东西，比如......

import email
b = email.message_from_string(a)
bbb = b['body']

?

4

7 回答 7

132

To be highly positive you work with the actual email body (yet, still with the possibility you're not parsing the right part), you have to skip attachments, and focus on the plain or html part (depending on your needs) for further processing.

As the before-mentioned attachments can and very often are of text/plain or text/html part, this non-bullet-proof sample skips those by checking the content-disposition header:

b = email.message_from_string(a)
body = ""

if b.is_multipart():
    for part in b.walk():
        ctype = part.get_content_type()
        cdispo = str(part.get('Content-Disposition'))

        # skip any text/plain (txt) attachments
        if ctype == 'text/plain' and 'attachment' not in cdispo:
            body = part.get_payload(decode=True)  # decode
            break
# not multipart - i.e. plain text, no attachments, keeping fingers crossed
else:
    body = b.get_payload(decode=True)

BTW, walk() iterates marvelously on mime parts, and get_payload(decode=True) does the dirty work on decoding base64 etc. for you.

Some background - as I implied, the wonderful world of MIME emails presents a lot of pitfalls of "wrongly" finding the message body. In the simplest case it's in the sole "text/plain" part and get_payload() is very tempting, but we don't live in a simple world - it's often surrounded in multipart/alternative, related, mixed etc. content. Wikipedia describes it tightly - MIME, but considering all these cases below are valid - and common - one has to consider safety nets all around:

Very common - pretty much what you get in normal editor (Gmail,Outlook) sending formatted text with an attachment:

multipart/mixed
 |
 +- multipart/related
 |   |
 |   +- multipart/alternative
 |   |   |
 |   |   +- text/plain
 |   |   +- text/html
 |   |      
 |   +- image/png
 |
 +-- application/msexcel

Relatively simple - just alternative representation:

multipart/alternative
 |
 +- text/plain
 +- text/html

For good or bad, this structure is also valid:

multipart/alternative
 |
 +- text/plain
 +- multipart/related
      |
      +- text/html
      +- image/jpeg

Hope this helps a bit.

P.S. My point is don't approach email lightly - it bites when you least expect it :)

于 2015-09-29T09:30:58.897 回答
98

使用Message.get_payload

b = email.message_from_string(a)
if b.is_multipart():
    for payload in b.get_payload():
        # if payload.is_multipart(): ...
        print payload.get_payload()
else:
    print b.get_payload()
于 2013-07-26T06:30:58.110 回答
13

有一个非常好的包可用于使用适当的文档来解析电子邮件内容。

import mailparser

mail = mailparser.parse_from_file(f)
mail = mailparser.parse_from_file_obj(fp)
mail = mailparser.parse_from_string(raw_mail)
mail = mailparser.parse_from_bytes(byte_mail)

如何使用：

mail.attachments: list of all attachments
mail.body
mail.to
于 2018-03-15T09:05:38.620 回答
12

Python 3.6+ 提供了内置的便利方法来查找和解码纯文本正文，如@Todor Minakov's answer。您可以使用EMailMessage.get_body()和get_content()方法：

msg = email.message_from_string(s, policy=email.policy.default)
body = msg.get_body(('plain',))
if body:
    body = body.get_content()
print(body)

None请注意，如果没有（明显的）纯文本正文部分，这将给出。

如果您正在读取例如 mbox 文件，您可以给邮箱构造函数一个EmailMessage工厂：

mbox = mailbox.mbox(mboxfile, factory=lambda f: email.message_from_binary_file(f, policy=email.policy.default), create=False)
for msg in mbox:
    ...

请注意，您必须email.policy.default作为策略传递，因为它不是默认值...

于 2020-05-10T06:53:57.517 回答
4

python中没有b['body']。您必须使用 get_payload。

if isinstance(mailEntity.get_payload(), list):
    for eachPayload in mailEntity.get_payload():
        ...do things you want...
        ...real mail body is in eachPayload.get_payload()...
else:
    ...means there is only text/plain part....
    ...use mailEntity.get_payload() to get the body...

祝你好运。

于 2013-07-26T06:36:48.917 回答
1

如果 emails 是 pandas 数据框并且 emails.message 是电子邮件文本的列

## Helper functions
def get_text_from_email(msg):
    '''To get the content from email objects'''
    parts = []
    for part in msg.walk():
        if part.get_content_type() == 'text/plain':
            parts.append( part.get_payload() )
    return ''.join(parts)

def split_email_addresses(line):
    '''To separate multiple email addresses'''
    if line:
        addrs = line.split(',')
        addrs = frozenset(map(lambda x: x.strip(), addrs))
    else:
        addrs = None
    return addrs 

import email
# Parse the emails into a list email objects
messages = list(map(email.message_from_string, emails['message']))
emails.drop('message', axis=1, inplace=True)
# Get fields from parsed email objects
keys = messages[0].keys()
for key in keys:
    emails[key] = [doc[key] for doc in messages]
# Parse content from emails
emails['content'] = list(map(get_text_from_email, messages))
# Split multiple email addresses
emails['From'] = emails['From'].map(split_email_addresses)
emails['To'] = emails['To'].map(split_email_addresses)

# Extract the root of 'file' as 'user'
emails['user'] = emails['file'].map(lambda x:x.split('/')[0])
del messages

emails.head()
于 2018-08-28T06:10:07.000 回答
-3

这是每次都适用于我的代码（适用于 Outlook 电子邮件）：

#to read Subjects and Body of email in a folder (or subfolder)

import win32com.client  
#import package

outlook = win32com.client.Dispatch("Outlook.Application").GetNamespace("MAPI")  
#create object

#get to the desired folder (MyEmail@xyz.com is my root folder)

root_folder = 
outlook.Folders['MyEmail@xyz.com'].Folders['Inbox'].Folders['SubFolderName']

#('Inbox' and 'SubFolderName' are the subfolders)

messages = root_folder.Items

for message in messages:
if message.Unread == True:    # gets only 'Unread' emails
    subject_content = message.subject
# to store subject lines of mails

    body_content = message.body
# to store Body of mails

    print(subject_content)
    print(body_content)

    message.Unread = True         # mark the mail as 'Read'
    message = messages.GetNext()  #iterate over mails
于 2019-01-30T08:16:24.783 回答