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我以为我以前做过这样的事情:

$reg = mysql_query ("(SELECT count(*) from vouchers) as total_vouchers), 
                     (SELECT count(*) from vouchers WHERE asignado = 1) as vouchers_asignados,
                     (SELECT count(*) from crm) as crm_users,
                     (SELECT count(*) from datos_modificados) as dm_users") or die(mysql_error());

但它会在第一个附近返回 mysql_error ,

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'as total_vouchers), ((SELECT count(*) from vouchers WHERE asignado = 1) a' at line 1

知道为什么吗?

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1 回答 1

3

尝试添加select如下

$reg = mysql_query ("SELECT
                     (SELECT count(*) from vouchers) as total_vouchers, 
                     (SELECT count(*) from vouchers WHERE asignado = 1) as vouchers_asignados,
                     (SELECT count(*) from crm) as crm_users,
                     (SELECT count(*) from datos_modificados) as dm_users") or die(mysql_error());
于 2013-07-24T11:34:54.653 回答