1

我有一个实体“员工”,它与一个或多个“经理”实体相关联。因此,我在员工实体中使用连接表和关联,如下所示:

/**
* @ManyToMany(targetEntity="manager_entity")
* @JoinTable(name="manager_employees",
* joinColumns={@JoinColumn(name="emp_id", referencedColumnName="id")},
* inverseJoinColumns={@JoinColumn(name="manager_id", referencedColumnName="id", unique=true)}
* )
*/
protected $managers;

这已经在起作用了。但现在我想检索特定经理的所有员工。因此我问是否有可能做这样的事情:

$mgr = $this->em->getRepository ( 'Entities\manager' )->findOneBy ( array (
                "alias" => $this->get('alias'));
// only pseudo code - i know that $managers is a list of managers and $mgr cannot be compared to that
$empList = $this->em->getRepository('Entities\employee')->findBy(array("managers" => $mgr));
4

1 回答 1

0

将这样的函数添加到您的存储库:

public function findByManager($managerId)
{
    return $this->getEntityManager()
        ->createQueryBuilder()
        ->from('employee', 'e')
        ->innerJoin('e.managers m')
        ->where('m.Id = :managerId')
        ->setParameter('managerId', $managerId)
        ->getQuery()
        ->getResult();
}

然后只需使用:

$employee = $repository->findByManager($manager->getId());
于 2015-12-01T11:48:45.650 回答