batch-file - 提取路径直到批处理中最后一次出现“\”

Question

任务很简单：给定路径：C:\Auto\proj 输出：C:\Auto。即提取给定路径，直到但不包括批处理中最后一次出现的“\”。

Answer 1

尝试这个：

set "givenpath=C:\Auto\proj"
for /f "tokens=1,2 delims=\" %%a in ("%givenpath%") do set "givenpath=%%a\%%b"
echo %givenpath%

Answer 2

尝试这个：

@echo off

setlocal EnableDelayedExpansion

set "givenPath=C:\Auto\proj"

for %%f in (%givenPath%) do (
  set "parentPath=%%~dpf"
  set "parentPath=!parentPath:~0,-1!"
)

echo %parentPath%

另外的选择：

@echo off

setlocal

set "givenPath=C:\Auto\proj"
call :Dirname "%givenPath%"
goto :eof

:Dirname
set "parentPath=%~dp1"
set "parentPath=!parentPath:~0,-1!"
echo %parentPath%"

或者您可以将路径作为命令行参数传递：

@echo off

setlocal

set "parentPath=%~dp1"
set "parentPath=!parentPath:~0,-1!"
echo %parentPath%"