对于那些使用Google JSON 模式生成图表数据并且无法让 NumberFormat 与 ChartWrapper 一起使用的用户,您可以将格式直接应用于“f”行:null
要注意:
使用数据表 > 确定
var chart = new google.visualization.PieChart(document.getElementById('chart'));
var dataTable = new google.visualization.DataTable(data);
var formatter = new google.visualization.NumberFormat({prefix: '$'});
formatter.format(dataTable, 1);
使用 ChartWrapper > BAD
var formatter = new google.visualization.NumberFormat({prefix: '$'});
formatter.format(data, 1);
var wrapper = new google.visualization.ChartWrapper({
chartType: 'PieChart',
dataTable: data,
options: myPieChartOptions(),
containerId: 'chart_div'
});
这就是我使用 Google JSON 正确格式化数据的方式。
示例 JSON:
{
"cols": [
{"id":"","label":"Product","pattern":"","type":"string"},
{"id":"","label":"Sales","pattern":"","type":"number"}
],
"rows": [
{"c":[{"v":"Nuts","f":null},{"v":945.59080870918,"f":"$945.59"}]}
]
}
这是生成该 JSON 的 PHP 代码
setlocale(LC_MONETARY, 0);
// init arrays
$result['cols'] = array();
$result['rows'] = array();
// add col data
$result['cols'][] = array(
"id" => "",
"label" => "Product",
"pattern" => "",
"type" => "string"
);
$result['cols'][] = array(
"id" => "",
"label" => "Sales",
"pattern" => "",
"type" => "number"
);
$nutsTotalFormat = "$".number_format($nutsTotal, 2);
$result['rows'][]["c"] = array(array("v" => "Nuts","f" => null),array("v" => $nutsTotal,"f" => $nutsTotalFormat ));
饼图将显示 $nutsTotalFormat 的格式化结果
“945.59 美元”