0

提前致谢。在我的应用程序中，我有一个表格视图，其中我必须使用两种不同样式的自定义单元格，我制作了两个自定义单元格，在 tableView cellForRowAtIndexPath 方法中，我使用了两个单元格标识符，即使我尝试了两个部分。但它不工作。它给了我“EXE BAD Excess”或其他一些错误。下面是我的代码。

错误：thread1_EXE_BAD_Access（代码 = 2，地址 0 x 0）

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:   (NSIndexPath *)indexPath
{

//CatIdentifier
static NSString *CellIdentiFier = @"CatIdentifier";
static NSString *Cell1IdentiFier = @"CatIdentifier1";

if (indexPath.section == 0)
{
   CommitteCell *cell = ( CommitteCell *)[tableView dequeueReusableCellWithIdentifier:CellIdentiFier];

    if(cell == nil)
    {

       cell = ( CommitteCell *)[[[NSBundle mainBundle] loadNibNamed:@"CommitteeCell" owner:self options:nil] objectAtIndex:0];

    }

    if (indicator == 1)
    {
      cell.lblName.text = str;

    }
    else
    {
      cell.lblName.text = [arrayName objectAtIndex:indexPath.row];
      cell.lblPost.text = [arrayPost objectAtIndex:indexPath.row];
      cell.picimg.image = [UIImage imageWithData:[NSData dataWithContentsOfURL:[NSURL URLWithString:[arrayimage objectAtIndex:indexPath.row]]]];

    }

    cell.backgroundView = [[UIImageView alloc]init];

    UIImage *img  = [UIImage imageNamed:@"link-bg 2.png"];

    ((UIImageView *)cell.backgroundView).image = img;


    return cell;
}


else 
{
    Committee2Cell *cell1 = (Committee2Cell  *)[tableView dequeueReusableCellWithIdentifier:Cell1IdentiFier];
    if(cell1 == nil)
    {

        cell1 = (Committee2Cell  *)[[[NSBundle mainBundle] loadNibNamed:@"Committee2Cell" owner:self options:nil] objectAtIndex:0];

    }

    cell1.lblPost1.text = strPost;
    cell1.txtName.text = strName;


    cell1.backgroundView = [[UIImageView alloc]init];

    UIImage *img  = [UIImage imageNamed:@"link-bg 2.png"];

    ((UIImageView *)cell1.backgroundView).image = img;

    return cell1;
 }

}

表视图中的部分和部分方法中的行如下。

- (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView
{
 return 2;
}

- (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section
{
 switch (section)
 {
    case 0:
        return [arrayName count]-1;
        break;
    case 1:
        return 1;
        break;
    default:
        break;
  }

  return 0;
 }

请如果有人可以罚款我的错误在哪里。再次感谢。

数组和标签的数据如下。

-(void)NewsParser:(NSMutableDictionary *)dic { NSLog(@"dic = %@",dic);

  arrayName = [[NSMutableArray alloc]init];
  arrayPost = [[NSMutableArray alloc]init];
  arrayimage= [[NSMutableArray alloc]init];

  strPost = [[NSString alloc]init];
  strName = [[NSString alloc]init];

  strPost = [[dic valueForKey:@"post"]objectAtIndex:8];
  strName = [[dic valueForKey:@"name"]objectAtIndex:8];

  NSLog(@"Name = %@",strName);
  NSLog(@"Post = %@",strPost);


  for(int i=0;i<[dic count]-1;i++)
  {
    [arrayName addObject:[[dic valueForKey:@"name"]objectAtIndex:i]];
    [arrayPost addObject:[[dic valueForKey:@"post"]objectAtIndex:i]];
    [arrayimage addObject:[[dic valueForKey:@"pic"]objectAtIndex:i]];
  }

  NSLog(@"array  = %@",arrayName);
  NSLog(@"array  = %@",arrayPost);
  NSLog(@"array  = %@",arrayimage);

  [table1 reloadData];


}
4

4 回答 4

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我认为更简洁的方法是使用具有两种不同类型单元格的容器视图，然后有选择地显示/隐藏与该单​​元格相关的视图。这将更容易编码和维护，但可能会消耗更多内存。

于 2013-07-17T09:33:55.537 回答
0

使用喜欢在我的代码中顺利完成它的工作，如果您需要更多帮助，请告诉我：

-(UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath {
if(YOUR CONDITION HERE)
       ShareActionViewCell *shareCell;
        NSString *ShareCellId = [NSString stringWithFormat:@"ShareCell%d",indexPath.row];
        shareCell = (ShareActionViewCell *)[tableView dequeueReusableCellWithIdentifier:ShareCellId];
        if(!shareCell) {
            shareCell = [[ShareActionViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:ShareCellId];
        }
        shareCell.selectionStyle = UITableViewCellSelectionStyleNone;
        shareCell.ShareTitle.text = [NSString stringWithFormat:@"%@",[tbldata objectAtIndex:indexPath.row]];


    } else {

        CustCell *dataCell;
        NSString *DataCellId = [NSString stringWithFormat:@"DataCell%d",indexPath.row];
        dataCell = (CustCell *)[tableView dequeueReusableCellWithIdentifier:DataCellId];
        if(!dataCell) {
            dataCell = [[CustCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:DataCellId];
        }
        shareCell.selectionStyle = UITableViewCellSelectionStyleNone;
        shareCell.ShareTitle.text = [NSString stringWithFormat:@"%@",[tbldata objectAtIndex:indexPath.row]];

}
}
于 2013-07-17T14:07:05.200 回答
0

  1. 建议-objectForKey用于字典：

    [[dic objectForKey:@"post"] objectAtIndex:8];

  2. 确保有一个 NSArray 对象在name// postkeyed pictodic

  3. 而且，在你的 for 循环中：

    for(int i=0;i< [dic count] -1;i++)
    {
    [arrayName addObject:[[dic valueForKey:@"name"] objectAtIndex: i ]];
    [arrayPost addObject:[[dic valueForKey:@"post"]objectAtIndex:i]];
    [arrayimage addObject:[[dic valueForKey:@"pic"]objectAtIndex:i]];
    }

你确定[dic count] <= [dic objectForKey:@"name"]吗？添加nil到数组将崩溃。

4.你在哪里调用的方法-(void)NewsParser:(NSMutableDictionary *)dic;，如果你的数据数组是正确的，可能是[table1 reloadData];崩溃了。

于 2013-07-17T11:54:03.963 回答
0

您 R 将可重用标识符设为仅一次。做这样的事情：

-(UITableViewCell *)tableView : (UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath{

       static NSString* identifier;
    if(indexPath.section == 0)
        identifier = @"0";
    else
        identifier = @"1";

   self.tableView.dataSource = self;

    UITableViewCell *cell = [self.tableView dequeueReusableCellWithIdentifier:identifier];

    if( cell == nil)
        cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:identifier] ;

if (indexPath.section == 0)
{

    if(cell == nil)
    {

       cell = ( CommitteCell *)[[[NSBundle mainBundle] loadNibNamed:@"CommitteeCell" owner:self options:nil] objectAtIndex:0];

    }

    if (indicator == 1)
    {
      cell.lblName.text = str;

    }
    else
    {
      cell.lblName.text = [arrayName objectAtIndex:indexPath.row];
      cell.lblPost.text = [arrayPost objectAtIndex:indexPath.row];
      cell.picimg.image = [UIImage imageWithData:[NSData dataWithContentsOfURL:[NSURL URLWithString:[arrayimage objectAtIndex:indexPath.row]]]];

    }

    cell.backgroundView = [[UIImageView alloc]init];

    UIImage *img  = [UIImage imageNamed:@"link-bg 2.png"];

    ((UIImageView *)cell.backgroundView).image = img;


    return cell;
}
于 2013-07-17T09:27:48.750 回答