10

我有这个脚本可以在文本中进行单词搜索。搜索进行得非常好，结果按预期工作。我想要实现的是提取n接近匹配的单词。例如：

世界很小，我们应该好好珍惜。

假设我正在寻找place，我需要提取右侧的 3 个单词和左侧的 3 个单词。在这种情况下，它们将是：

left -> [is, a, small]
right -> [we, should, try]

做到这一点的最佳方法是什么？

谢谢！

4

5 回答 5

22 
def search(text,n):
    '''Searches for text, and retrieves n words either side of the text, which are retuned seperatly'''
    word = r"\W*([\w]+)"
    groups = re.search(r'{}\W*{}{}'.format(word*n,'place',word*n), text).groups()
    return groups[:n],groups[n:]

这使您可以指定要捕获的任一方的字数。它通过动态构造正则表达式来工作。和

t = "The world is a small place, we should try to take care of it."
search(t,3)
(('is', 'a', 'small'), ('we', 'should', 'try'))
于 2013-07-15T02:19:22.180 回答
6

虽然正则表达式可以工作，但我认为这对于这个问题来说有点过分了。最好使用两个列表推导：

sentence = 'The world is a small place, we should try to take care of it.'.split()
indices = (i for i,word in enumerate(sentence) if word=="place")
neighbors = []
for ind in indices:
    neighbors.append(sentence[ind-3:ind]+sentence[ind+1:ind+4])

请注意，如果您要查找的单词在句子中连续出现多次，则此算法会将连续出现的单词包括为邻居。
例如：

在 [29] 中：邻居 = []

在[30]中：句子='世界是一个小地方地方地方，我们应该尽量照顾它。'.split()

In [31]: 句子 Out[31]: ['The', 'world', 'is', 'a', 'small', 'place', 'place', 'place,', 'we', '应该'，'尝试'，'to'，'take'，'care'，'of'，'it']

In [32]: indices = [i for i,word in enumerate(sentence) if word == 'place']

In [33]: for ind in indices:
   ....:     neighbors.append(sentence[ind-3:ind]+sentence[ind+1:ind+4])


In [34]: neighbors
Out[34]: 
[['is', 'a', 'small', 'place', 'place,', 'we'],
 ['a', 'small', 'place', 'place,', 'we', 'should']]
于 2013-07-15T02:06:21.443 回答
5 
import re
s='The world is a small place, we should try to take care of it.'
m = re.search(r'((?:\w+\W+){,3})(place)\W+((?:\w+\W+){,3})', s)
if m:
    l = [ x.strip().split() for x in m.groups()]
left, right = l[0], l[2]
print left, right

输出

['is', 'a', 'small'] ['we', 'should', 'try']

如果您搜索The，它会产生：

[] ['world', 'is', 'a']
于 2013-07-15T02:12:36.050 回答
4

处理搜索关键字多次出现的场景。例如下面是搜索关键字的输入文本：地点出现 3 次

The world is a small place, we should try to take care of this small place by planting trees in every place wherever is possible

这是功能

import re

def extract_surround_words(text, keyword, n):
    '''
    text : input text
    keyword : the search keyword we are looking
    n : number of words around the keyword
    '''
    #extracting all the words from text
    words = words = re.findall(r'\w+', text)
    
    #iterate through all the words
    for index, word in enumerate(words):

        #check if search keyword matches
        if word == keyword:
            #fetch left side words
            left_side_words = words[index-n : index]
            
            #fetch right side words
            right_side_words = words[index+1 : index + n + 1]
            
            print(left_side_words, right_side_words)

调用函数

text = 'The world is a small place, we should try to take care of this small place by planting trees in every place wherever is possible'
keyword = "place"
n = 3
extract_surround_words(text, keyword, n)

output : 
['is', 'a', 'small'] ['we', 'should', 'try']
['we', 'should', 'try'] ['to', 'microsot', 'is']
['also', 'take', 'care'] ['googe', 'is', 'one']
于 2021-04-27T17:26:53.883 回答
3

找出所有单词：

import re

sentence = 'The world is a small place, we should try to take care of it.'
words = re.findall(r'\w+', sentence)

获取您要查找的单词的索引：

index = words.index('place')

然后使用切片找到其他的：

left = words[index - 3:index]
right = words[index + 1:index + 4]
于 2013-07-15T02:02:23.463 回答