在 Octave/MATLAB 中,假设我有:
all =
{
[1,1] = one
[1,2] = two
[1,3] = three
[1,4] = four
[1,5] = five
[1,6] = six
[1,7] = seven
[1,8] = eight
[1,9] = nine
[1,10] = ten
}
some =
{
[1,1] = someword
[1,2] = someword
[1,3] = one
[1,4] = someword
[1,5] = nine
}
我将如何制作一个新矩阵
new =
{
[1,1] = 1
[1,2] = 0
[1,3] = 0
[1,4] = 0
[1,5] = 0
[1,6] = 0
[1,7] = 0
[1,8] = 0
[1,9] = 1
[1,10] = 0
}
也就是说,new
矩阵的大小与all
矩阵相同,但值是1
或0
,具体取决于 中的单词是否some
存在于all
?