mysql - 如何从表中获取最接近的日期值？输入参数为2012-02-10

Question

+------------+
| 日期 |
+------------+
| 2011-10-26 |
| 2011-11-01 |
| 2011-11-10 |
| 2011-11-24 |
| 2011-11-28 |
| 2011-12-05 |
| 2011-12-07 |
| 2011-12-19 |
| 2011-12-23 |
| 2011-12-28 |
| 2012-01-04 |
| 2012-01-10 |
| 2012-01-14 |
| 2012-01-20 |
| 2012-01-25 |
| 2012-02-02 |
| 2012-02-06 |
| 2012-02-21 |
| 2012-02-27 |
| 2012-03-01 |
+------------+

我不知道该怎么做。请帮忙 ：）

Answer 1

要获得与给定日期最接近的值，请按差值的绝对值排序：

select *
from t
order by abs(datediff(date, date('2012-02-10')))
limit 1