我必须编写一个方法,它能够在数据库中找到随机假期。但是当我在测试中使用这部分
Random id = new Random();
vacationId = id.nextInt(2500);
我明白了NullPoiterExeption。但是当我只是打印
vacationId = 2500;
或其他数字,一切正常。
这是整个方法
public Vacation findRandomVacation() {
    Integer vacationId = null;
    Query query = entityManager.createQuery("from Vacation v where v.id = :id")
                .setParameter("id", vacationId);
    if  ( query.getResultList().isEmpty()) {
        Random id = new Random();
        vacationId = id.nextInt(2500);
        query = entityManager.createQuery("from Vacation v where v.id = :id")
               .setParameter("id", vacationId);
    }
    return (Vacation) query.getResultList().get(0);
}
这是测试的主体:
@Test
public void testVacationApprovalResultDao () {
    Vacation testVacation = findRandomVacation();
    VacationApproval testVacationApproval = findVacationApprovalDAO(testVacation);
    List<VacationApprovalResult> testVacationApprovalResult = getVacationApprovalResultByManager(testVacationApproval);
    Set<VacationApprovalResult> setVacationApprovalResult = testVacationApproval.getVacationApprovalResults();   //mistake is here
    List<VacationApprovalResult> testVacationApprovalResult2 = new ArrayList<VacationApprovalResult> ();
    testVacationApprovalResult2.addAll(setVacationApprovalResult);
    assertEquals(testVacationApprovalResult, testVacationApprovalResult2);
}