0

我有一个 predicateWithFormat 错误导致我的应用程序崩溃。

有问题的代码是：

@implementation SecondViewController
{
NSArray *searchResults;
}

@synthesize jsonConnection, bakeryProductArray, bakeryTableView;

- (void)viewDidLoad
{
[super viewDidLoad];

// Do any additional setup after loading the view, typically from a nib.
[self retrieveData];
}

- (void)didReceiveMemoryWarning
{
[super didReceiveMemoryWarning];
// Dispose of any resources that can be recreated.
}

#pragma mark - UITableView DataSource

-(NSInteger)numberOfSectionsInTableView:(UITableView *)tableView
{
return 1;
}


-(NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section
{
if (tableView == self.searchDisplayController.searchResultsTableView) {
    return [searchResults count];
}
else {
return [bakeryProductArray count];

}
}

-(UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath     *)indexPath
{
static NSString *cellIdentifier = @"Cell";

UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:cellIdentifier];

if (cell == nil) {
    cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleSubtitle   reuseIdentifier:cellIdentifier];
}

if (tableView == self.searchDisplayController.searchResultsTableView) {
    cell.textLabel.text = [searchResults objectAtIndex:indexPath.row];
}
else {
foodProducts *currentProduct = [bakeryProductArray objectAtIndex:indexPath.row];
cell.textLabel.text = currentProduct.productName;
cell.detailTextLabel.text = currentProduct.productName;
cell.accessoryType = UITableViewCellAccessoryDisclosureIndicator;
}

return cell;

}

#pragma mark - UITableView Delegate methods

-(void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath
{
if (bakeryTableView == self.searchDisplayController.searchResultsTableView) {
    [self performSegueWithIdentifier: @"bakeryDetails" sender: self];
}

    detailedViewController *productinfo = [self.storyboard instantiateViewControllerWithIdentifier:@"bakeryDetails"];
    //Retrieve current user array
    foodProducts *currentProduct2 = [bakeryProductArray objectAtIndex:indexPath.row];
    productinfo.productName = currentProduct2.productName;
    productinfo.productImage = currentProduct2.productImgUrl;
    productinfo.productDescription = currentProduct2.productDescription;
    productinfo.productPrice = currentProduct2.productPrice;
    productinfo.productQuantity = currentProduct2.productquantity;
    productinfo.productAllergy = currentProduct2.productAllergy;

    [self.navigationController pushViewController:productinfo animated:YES];
    [bakeryTableView deselectRowAtIndexPath:indexPath animated:YES];
}


//Becareful here as wrong predicateWithFormat can crash app on keying in search 
-(void)filterContentForSearchText:(NSString *)searchText scope:(NSString *)scope
{
NSPredicate *resultPredicate = [NSPredicate predicateWithBlock:^BOOL(NSString * testString,    NSDictionary *bindings) {
    return ([searchText compare:testString options: NSCaseInsensitiveSearch] == NSOrderedSame);
}];

searchResults = [bakeryProductArray filteredArrayUsingPredicate:resultPredicate];
}


-(BOOL)searchDisplayController:(UISearchDisplayController *)controller
shouldReloadTableForSearchString:(NSString *)searchString
{
[self filterContentForSearchText:searchString
                           scope:[[self.searchDisplayController.searchBar scopeButtonTitles]
                                  objectAtIndex:[self.searchDisplayController.searchBar
                                                 selectedScopeButtonIndex]]];

return YES;
}


#pragma mark - methods

-(void) retrieveData
{
NSURL *url = [NSURL URLWithString:getDataUrl];
NSData *data = [NSData dataWithContentsOfURL:url];

jsonConnection = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:nil];
bakeryProductArray = [[NSMutableArray alloc]init];

for (int i = 0; i < jsonConnection.count; i++)
{
    NSString *pID = [[jsonConnection objectAtIndex:i] objectForKey:@"id"];
    NSString *pName = [[jsonConnection objectAtIndex:i] objectForKey:@"Name"];
    NSString *pImageUrl = [[jsonConnection objectAtIndex:i] objectForKey:@"ImageUrl"];
    NSString *pDescription = [[jsonConnection objectAtIndex:i] objectForKey:@"Description"];
    NSString *pQuantity = [[jsonConnection objectAtIndex:i] objectForKey:@"Quantity"];
    NSString *pPrice = [[jsonConnection objectAtIndex:i] objectForKey:@"Price"];
    NSString *pAllergy = [[jsonConnection objectAtIndex:i] objectForKey:@"Allergy"];

    foodProducts *myProducts = [[foodProducts alloc]initWithproductID:pID andproductName:pName andproductImgUrl:pImageUrl andproductDescription:pDescription andproductquantity:pQuantity andproductPrice:pPrice andproductAllergy:pAllergy];


    [bakeryProductArray addObject:myProducts];
}


[self.bakeryTableView reloadData];

}

食品类

@implementation foodProducts
@synthesize productID, productName, productImgUrl, productquantity,productDescription, productPrice, productAllergy;

-(id) initWithproductID:(NSString *)uproductID andproductName:(NSString *)uproductName andproductImgUrl:(NSString *)uproductImage andproductDescription:(NSString *)uproductDescription andproductquantity:(NSString *)uproductquantity andproductPrice:(NSString *)uproductPrice andproductAllergy:(NSString *)uproductAllergy
{
self = [super init];
if  (self)
{
    productID = uproductID;
    productName = uproductName;
    productImgUrl = uproductImage;
    productquantity = uproductquantity;
    productDescription = uproductDescription;
    productPrice = uproductPrice;
    productAllergy = uproductAllergy;

}
return self;
}

输入 NSPredicate 的数组是@property (nonatomic, strong) NSMutableArray *bakeryProductArray;

错误说：不能在集合中使用 in/contains 运算符

任何想法，关于什么是错的？

4

2 回答 2

1

您的数组不包含字符串，而是自定义foodProducts对象。

要按“产品名称”过滤对象，您可以使用

[NSPredicate predicateWithFormat:@"productName CONTAINS[cd] %@", searchText];

添加：您的代码中还有另一个错误：

cell.textLabel.text = [searchResults objectAtIndex:indexPath.row];

无法工作，因为右侧不返回字符串。它应该是

foodProducts *currentProduct = [searchResults objectAtIndex:indexPath.row];
cell.textLabel.text = currentProduct.productName;
于 2013-07-09T19:52:33.940 回答
0

NSPredicate *resultPredicate = [NSPredicate predicateWithFormat:@"self.productName contains[cd] %@", searchText];

NSArray *searchResults = [self.bakeryProductArray filteredArrayUsingPredicate:resultPredicate];

NSLog(@"%@",searchResults);

如果以上不起作用，您可以显示您的 foodProduct 类（模型）。

理想情况下，您应该使用 like[cd] 而不是 contains[cd]。

参考： http: //developer.apple.com/library/ios/#documentation/cocoa/conceptual/Predicates/Articles/pSyntax.html 1 CONTAINS 左边的表达式包含右边的表达式。

2 LIKE 左边的表达式等于右边的表达式： ? 和 * 允许作为通配符，在哪里？匹配 1 个字符， * 匹配 0 个或更多字符。

于 2013-07-09T20:38:11.097 回答