我想在像这个cytoscape 示例这样的力布局中为线提供动态贝塞尔曲线,在 d3 中是否可行?请参阅此d3 示例,但使用 arc。我不知道算法,有人有想法吗?
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我已经看到了cytoscape库,并且使用这个算法可以工作
function tick() {
path.attr("d", function (d) {
var coordinatesP = findEdgeControlPoints(d);
return "M" + d.source.x + "," + d.source.y + "S" + coordinatesP.xp + "," + coordinatesP.yp + " " + d.target.x + "," + d.target.y;
});
hashTable = {};
nodes.attr("cx", function (d) { return d.x; })
.attr("cy", function (d) { return d.y; });
}
var findEdgeControlPoints = function (d) {
var midPointX = (d.source.x + d.target.x) / 2;
var midPointY = (d.source.y + d.target.y) / 2;
var displacementX, displacementY;
displacementX = d.target.y - d.source.y;
displacementY = d.source.x - d.target.x;
var displacementLength = Math.sqrt(displacementX * displacementX + displacementY * displacementY);
displacementX /= displacementLength;
displacementY /= displacementLength;
var distanceFromMidpoint = findPathDeltaControlPoint(d);
var xp = midPointX + displacementX * distanceFromMidpoint;
var yp = midPointY + displacementY * distanceFromMidpoint;
return {xp : xp, yp : yp};
};
var findPathDeltaControlPoint = function (edge) {
/*caso statico il primo al centro e tutti gli altri ai lati*/
/*conto le occorrenze */
var pairId,
delta,
TICK = 20;
pairId = edge.source.id > edge.target.id ?
edge.target.id + '-' + edge.source.id :
edge.source.id + '-' + edge.target.id;
if (hashTable[pairId] == undefined) {
hashTable[pairId] = [];
}
if (edge[pairId] == undefined) {
edge[pairId] = [];
}
if (edge[pairId].length == 0) {
edge[pairId].push(pairId);
}
hashTable[pairId].push(edge);
// Ceck if is the first occurence
var pairIdOccurence = hashTable[pairId].length;
if (pairIdOccurence == 1) {
delta = 0;
} else if (pairIdOccurence > 1) {
// Check if is equal
if (pairIdOccurence % 2 == 0) {
delta = (TICK * pairIdOccurence) / 2;
} else {
delta = -((TICK * (pairIdOccurence - 1)) / 2);
}
}
return delta;
};
于 2013-07-17T10:08:12.373 回答