我有一个这样的实体:
@Entity
@Table(name = "PERSON_TB")
public class Person implements Serializable {
private static final long serialVersionUID = 32423423432434;
@Id
@Column(name = "ID")
private Long personId;
@Id
@Column(name = "VALUE")
private String value;
@Column(name = "NAME")
private String name;
@Transient
Address address;
//getters / setters
}
这是我创建实体的代码:
public Person createPerson( long id, String name, String value ) {
Person p = new Person();
p.setId(id);
p.setName(name);
p.setValue(value);
return p;
}
用另一种方法:
personCrudSvc.create(createPerson(192L, "Joe", "xyz");
这是错误:
java.sql.SQLException: Attempt to insert null into a non-nullable column: column: VALUE
table: PERSON_TB in statement [insert into PERSON_TB (NAME, ID) values (?, ?)]
不确定这是否与此错误有关:
我还有另外两个这样创建的表,这些都很好。