我不知道该怎么做。我写了一个函数,编译它没有错误,但是当我运行我得到的代码时:
ORA-0650: line 3, column 14:
PLS-00103: Encountered the symbol "/" when expecting one of the following:
:= . ( @ % ; not null range default character
ORA-06512: at line 58
Vendor code 6550
这是功能:
create or replace
FUNCTION "GET_MUSICIAN_FUN"
(
i_mus_id IN musicians.id%type
)
RETURN musicians%ROWTYPE
AS
o_mus_rec musicians%ROWTYPE;
BEGIN
SELECT m.id, m.first_name, m.last_name, m.born, m.died , m.picture_path, m.bio
INTO o_mus_rec
FROM musicians m
WHERE id = i_mus_id;
RETURN o_mus_rec;
EXCEPTION
WHEN NO_DATA_FOUND THEN
RAISE_APPLICATION_ERROR(-20005, 'Found nothing.');
WHEN TOO_MANY_ROWS THEN
RAISE_APPLICATION_ERROR(-20006, 'Found too many.');
WHEN OTHERS THEN
RAISE_APPLICATION_ERROR(-20007, 'Cannot get musician.');
END GET_MUSICIAN_FUN;
编辑:
当我调用它时:
declare
result musicians%rowtype;
begin
result := get_musician_fun(53);
end;
/
我得到:"anonymous block completed"
但是当从 PHP 调用它时:
$con = oci_connect("yoni", "yoni", "//localhost/xe");
$s = oci_parse($con, "begin :rc := GET_MUSICIAN_FUN(53); end;");
$rc = oci_new_cursor($con);
oci_bind_by_name($s, ":rc", $rc, -1, OCI_B_CURSOR);
oci_execute($s); // line 41
oci_execute($rc, OCI_DEFAULT);
oci_fetch_all($rc, $res, null, -1, OCI_FETCHSTATEMENT_BY_ROW); // line 43
return $res;
我得到:
Warning
: oci_execute(): ORA-06550: line 1, column 14:
PLS-00382: expression is of wrong type
ORA-06550: line 1, column 7:
PL/SQL: Statement ignored in... on line 41
Warning
: oci_fetch_all(): ORA-24338: statement handle not executed in... on line 43