2

我的代码应该引用我相信的 login_process.php 页面，但它没有返回任何内容。无论是错误消息还是成功消息。我看不出有什么问题，并尝试了一些不同的方法来使其正常工作。isset($_POST['login'])当我在它显示的内容之外回显某些内容时。但在里面，什么都没有。这就是让我相信这是一个问题......但我不太确定。

PHP代码：

<?php 
ob_start();
require 'db.php';
if(isset($_POST['login'])) {

    $date = date("F j, Y, g:i a"); 

    $username = $_POST['username'];
    $password = sha1($_POST['password']);
    // VARS
    $username = stripslashes($username);
    $username = strip_tags($username);
    $username = mysql_real_escape_string($username);

    $password = stripslashes($password);
    $password = strip_tags($password);
    $password = mysql_real_escape_string($password);

    // SELECT DB
    $sql = "SELECT * FROM `users` WHERE `username` = '$username' AND `password` = '$password'";
    $result = mysql_query($sql) or die ( mysql_error() );

    if (mysql_num_rows($result) != 0) {
         session_start();
         $row = mysql_fetch_array($result);
         $_SESSION['loggedIn'] = "true";
         $_SESSION['username'] = $username;
         $_SESSION['ip'] = $_SERVER['REMOTE_ADDR'];
         header("refresh: 2; bet_gg.php");

         echo '<div class="alert success hideit" style="width: 50%;">
         <p> Success.  You will be redirected.</p>
         <span class="close"></span></div>';


    } else {
         $_SESSION['loggedIn'] = "false";



                 echo ' 
        <div class="alert error hideit" style="width: 50%;">
        <p>There was an error with your log-in.</p>
        <span class="close"></span>
        </div><!-- End error -->';



         }
    }

   ?>

HTML 代码：

    <form action="login_process.php" method="POST" id="myForm">   
    <div class="two-thirds column">
      <div class="who">
        <h2 class="title">Log-In<span class="line"></span></h2>
       <div class="form-box">
        <label>Username <small>(required)</small></label>
        <input type="text" name="username" class="text">
      </div><!-- End Box -->
      <div class="form-box">
        <label>Password <small>(required)</small></label>
        <input type="password" name="password" class="text">
      </div><!-- End Box -->
      <div class="form-box">
        <button type="submit" clas="button medium color sub" name="login" class="button medium color sub" value="Log-In">Log-In</button>
      </div><!-- End Box -->
        <br /><br />
      </div>
    </div><!-- End who we are -->
    <span id="result"></span>
   </form>

jQuery代码：

    $("#sub").click( function() {
 $.post( $("#myForm").attr("action"), 
         $("#myForm :input").serializeArray(), 
         function(info){ $("#result").html(info); 
   });
});

$("#myForm").submit( function() {
  return false; 
});
4

2 回答 2

1

我没有看到#sub，但明显的提交按钮有name="login"。根据文档

由于未使用按钮提交表单，因此未序列化提交按钮值

isset($_POST['username'])改为检查。

于 2013-07-06T23:32:10.567 回答
0

将您的 javascript 代码更改为这样的内容

$("#myForm").submit(function(e) {
  e.preventDefault();
  $.post( $(this).attr("action"), $(this).serialize()+"&login=1", function( info ) {
    $("#result").html(info);
  }); 
});
于 2013-07-06T23:33:08.103 回答