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我有多个玩家在不同时间点进行的游戏的结果。我从两个不同的来源获得了这些信息，它们为每个玩家分配了不同的唯一 ID。我想找到一种雄辩的方法来通过玩家 id 匹配两个数据源。两个数据源

sourcex <- structure(list(outcomedate = structure(c(12637, 12637, 12637, 
12637, 12637, 12637, 12637, 12637, 12637, 12637, 12637, 12638, 
12639, 12640, 12640, 12640, 12640, 12640, 12640, 12640, 12640, 
12641, 12641, 12641, 12643, 12644, 12644, 12644, 12644, 12644, 
12644, 12644, 12644, 12644, 12644, 12645), class = "Date"), xid1 = c(206L, 
208L, 209L, 216L, 233L, 235L, 239L, 241L, 250L, 253L, 259L, 238L, 
236L, 211L, 221L, 234L, 249L, 254L, 255L, 257L, 258L, 207L, 230L, 
248L, 258L, 207L, 211L, 230L, 234L, 236L, 248L, 249L, 254L, 255L, 
257L, 221L), xid2 = c(211L, 207L, 221L, 249L, 248L, 257L, 234L, 
255L, 236L, 258L, 254L, 230L, 241L, 253L, 235L, 238L, 208L, 233L, 
239L, 259L, 206L, 209L, 250L, 216L, 259L, 216L, 241L, 208L, 235L, 
239L, 253L, 250L, 209L, 238L, 206L, 233L), outcome1 = c(2L, 1L, 
0L, 2L, 1L, 3L, 1L, 1L, 2L, 2L, 0L, 2L, 3L, 3L, 1L, 0L, 2L, 0L, 
0L, 0L, 2L, 1L, 2L, 1L, 0L, 3L, 2L, 0L, 0L, 0L, 2L, 2L, 2L, 1L, 
1L, 1L), outcome2 = c(0L, 0L, 0L, 1L, 1L, 2L, 1L, 1L, 1L, 2L, 
0L, 1L, 0L, 1L, 0L, 0L, 1L, 2L, 0L, 2L, 1L, 2L, 2L, 1L, 1L, 2L, 
2L, 0L, 1L, 1L, 2L, 1L, 0L, 1L, 1L, 3L)), .Names = c("outcomedate", 
"xid1", "xid2", "outcome1", "outcome2"), row.names = c(NA, 36L
), class = "data.frame")

sourcey <- structure(list(outcomedate = structure(c(12637, 12637, 12637, 
12637, 12637, 12637, 12637, 12637, 12637, 12637, 12637, 12638, 
12639, 12640, 12640, 12640, 12640, 12640, 12640, 12640, 12640, 
12641, 12641, 12641, 12643, 12644, 12644, 12644, 12644, 12644, 
12644, 12644, 12644, 12644, 12644, 12645), class = "Date"), yid1 = c(56, 
46, 67, 68, 59, 63, 55, 50, 66, 61, 57, 58, 53, 60, 64, 48, 69, 
54, 51, 65, 62, 47, 49, 52, 64, 60, 47, 48, 69, 49, 54, 51, 65, 
53, 52, 62), yid2 = c(47, 51, 64, 48, 62, 69, 53, 54, 60, 49, 
65, 52, 50, 63, 57, 56, 61, 46, 58, 67, 66, 59, 68, 55, 63, 57, 
68, 55, 59, 67, 58, 66, 50, 46, 56, 61), outcome1 = structure(c(1L, 
1L, 2L, 2L, 3L, 3L, 2L, 1L, 4L, 1L, 2L, 2L, 4L, 3L, 2L, 2L, 3L, 
3L, 3L, 4L, 1L, 1L, 1L, 2L, 3L, 1L, 4L, 2L, 2L, 2L, 1L, 3L, 2L, 
3L, 3L, 1L), .Label = c("1", "2", "0", "3", "4", "5", "6"), class = "factor"), 
    outcome2 = structure(c(1L, 2L, 3L, 2L, 1L, 1L, 2L, 2L, 3L, 
    2L, 1L, 2L, 1L, 3L, 2L, 2L, 3L, 1L, 1L, 2L, 1L, 3L, 2L, 3L, 
    2L, 2L, 3L, 2L, 1L, 3L, 2L, 2L, 3L, 2L, 1L, 4L), .Label = c("0", 
    "1", "2", "3", "4"), class = "factor")), .Names = c("outcomedate", 
"yid1", "yid2", "outcome1", "outcome2"), row.names = c(NA, 36L
), class = "data.frame")

两个来源都有一个outcomedate, outcome1,outcome2共同点。他们为游戏中的各个玩家分配不同的 ID。我已经完成了以下操作来查找 id 之间的匹配。

sourcex$ID <- with(sourcex, paste0(outcomedate, outcome1, outcome2))
sourcey$ID <- with(sourcey, paste0(outcomedate, outcome1, outcome2))

uPlayersx <- with(sourcex, unique(c(xid1, xid2)))
uPlayersy <- with(sourcey, unique(c(yid1, yid2)))

comparex <- sapply(uPlayersx, function(x){
  paste0(with(sourcex, ID[xid1 == x| xid2 == x]), collapse = '~')
})

comparey <- sapply(uPlayersy, function(x){
  paste0(with(sourcey, ID[yid1 == x| yid2 == x]), collapse = '~')
})

dumMatch <- data.frame(xid = uPlayersx, yid = uPlayersy[match(comparex, comparey)])

它在这个测试数据集上工作正常，但是真正的应用程序更大，这感觉就像一个 hack。此外，真实数据集在报告等方面可能存在错误，因此可能需要部分匹配。任何帮助，将不胜感激。

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1 回答 1

1

这将（至少）帮助过滤掉完美匹配的日期：

match.day <- function(d)
{
    tempx <- sourcex[sourcex$outcomedate==d,]
    tempy <- sourcey[sourcey$outcomedate==d,]

    if(nrow(tempx)!=nrow(tempy)) stop("matching failed: number of rows differ.")

    P <- outer(tempx$outcome1, tempy$outcome1, `==`) &
         outer(tempx$outcome2, tempy$outcome2, `==`)

    if(any(rowSums(P)!=1)) stop("maching failed: ambiguous or impossible assignment.")

    map <- P %*% seq_len(nrow(tempy))

    cbind(tempx[,c("xid1","xid2")], tempy[map,c("yid1","yid2")])
}

days <- unique(c(sourcex$outcomedate, sourcey$outcomedate))

do.call(rbind, lapply(days[-c(1,4,7)], match.day))

请注意，它在第 1 天、第 4 天和第 7 天都失败了（请参阅 参考资料days[c(1,4,7)]）。

其他日子的结果：

   xid1 xid2 yid1 yid2
12  238  230   58   52
13  236  241   53   50
22  207  209   47   59
23  230  250   52   55
24  248  216   49   68
25  258  259   64   63
36  221  233   62   61
于 2013-07-06T03:18:24.310 回答