我花了很多时间搜索问题出在哪里，但我没有找到任何东西。
它说“testAdd 导致错误：缺少参数”。当我运行测试时，只是没有执行 dataProvider 。我试图将 die() 放入 dataProvider 并没有死。
这是我的代码：
class LabelEntityModelTest extends PHPUnit_Extensions_Database_TestCase
{
private static $connection = NULL;
/**
* @var \CXNS\DB\Connections\Connection
*/
private static $appConnection;
private static $table;
public function __construct()
{
if (self::$connection) {
return;
}
$pdo = new \PDO($GLOBALS['DB_DSN'], $GLOBALS['DB_USER'], $GLOBALS['DB_PASSWD']);
self::$appConnection = new \CXNS\DB\Connections\Connection(array("prefix" => "test_", "driver" => "pdo", "resource" => $pdo));
self::$appConnection->connect();
self::$connection = $this->createDefaultDBConnection($pdo, 'mysql');
self::$table = $this->createXMLDataSet(__DIR__ . '/fixtures/tables.xml');
}
protected function getDataSet()
{
return self::$table;
}
public function getConnection()
{
return self::$connection;
}
public function getAppConnection()
{
return self::$appConnection;
}
/**
* @group onlyThis
* @dataProvider providerAdd
*/
public function testAdd($labelId, $entityId)
{
$lem = new \appLibs\Labels\LabelEntityModel($this->getAppConnection(), "contacts");
$lem->add($labelId, $entityId);
$count = $this->getAppConnection()
->select("id")
->from("label_relationships")
->where("label_id = %i", $labelId)
->where("table_ref_id = %i", $entityId)
->count();
$this->assertEquals(1, $count, "insert failed");
}
public function providerAdd()
{
return array(
array(2, 3),
array(3, 4),
array(3, 4),
array(3, 4),
array(3, 4),
array(3, 4),
array(5, 7)
);
}
}
谢谢您的帮助。