1 
log_date    log_time           emp_id    emp_name          log_action       
2013-06-16  08:48:48.0000000    30170   Sarah John          1
2013-06-16  16:48:48.0000000    30170   Sarah John          4
2013-06-15  07:18:48.0000000    30160   Paula Fred          1
2013-06-15  16:38:48.0000000    30160   Paula Fred          4

我有一个包含上述信息的日志表。我有一个查询来计算每个员工的每日工作时间并将它们存储在另一个的十进制字段中。问题是分钟已关闭，如果员工在同一天多次打卡/打卡，则会增加小时数。我希望它只考虑第一个好的打孔/打孔。

Select DISTINCT emp_id,log_date,SUM(datediff(Minute,stm, etm))/60.0
  as wrk_hrs from
(
    SELECT
        emp_id, log_date,
        log_time as etm,
        (
            SELECT top 1 log_time
            FROM tblLogs
            WHERE log_action = '1' and log_time <= a.log_time and emp_id=a.emp_id and a.log_date=log_date order by log_time desc
        ) as stm
    FROM tblLogs as a
    WHERE log_action = '4'
)as a
where stm is not null
group by log_date,emp_id,a.stm,a.etm;

是否有更准确的方法来计算小时和分钟并存储它们以供进一步计算。我需要一段时间和每周的总小时数来生成报告。

4

3 回答 3

0

如果您想要更高的准确性，请切换到秒：

Select emp_id,log_date,SUM(datediff(second,stm, etm))/3600.0
  as wrk_hrs from
(
    SELECT
        emp_id, log_date,
        log_time as etm,
        (
            SELECT top 1 log_time
            FROM tblLogs
            WHERE log_action = '1' and log_time <= a.log_time and emp_id=a.emp_id and a.log_date=log_date order by log_time desc
        ) as stm
    FROM tblLogs as a
    WHERE log_action = '4'
)as a
where stm is not null
group by log_date,emp_id,a.stm,a.etm;

注意： distinct使用时通常是完全多余的group by。

于 2013-07-04T02:20:21.223 回答
0

由于您只需要每个员工日操作的第一个条目：

SELECT
  [log_date],
  [emp_id],
  [emp_name],
  [1] AS [first_log_in],
  [4] AS [first_log_out],
  DATEDIFF(minute,[1],[4])/60.0 AS [hours]
FROM @tblLogs
PIVOT(MIN(log_time) FOR log_action IN ([1],[4])) p

这假设您的日志数据处于良好状态。如果您需要在打孔之前检查打孔或打孔之前的多个打孔，那是一个完全不同的问题。

于 2013-07-03T15:42:32.960 回答
0 
SELECT StartLog.emp_id, StartLog.log_date,  SUM(datediff(Minute,stm, etm))/60.0
FROM (
    SELECT emp_id, log_date, MIN(log_time) AS stm 
    FROM tblLogs
    WHERE log_action = '1'
    GROUP BY emp_id, log_date
    ) AS StartLog
INNER JOIN 
    (
        SELECT emp_id, log_date, MIN(log_time) AS etm 
        FROM tblLogs
        WHERE log_action = '4'
        GROUP BY emp_id, log_date
    ) AS EndLog
    ON StartLog.emp_id = EndLog.emp_id AND StartLog.log_date = EndLog.log_date
于 2013-07-03T15:54:35.480 回答