0

我遇到了一个问题,当我要求我的程序退出时,它会像我要求的那样打印,但是也会连续显示我的选项菜单。

所以我得到了这个:

>>> 
(S)huffle a message.
(U)nshuffle a message.
(Q)uit program.
Choose a option to begin: q
Goodbye!
(S)huffle a message.
(U)nshuffle a message.
(Q)uit program.
Choose a option to continue:

如果我选择“q”,我希望它在哪里显示:

>>> 
(S)huffle a message.
(U)nshuffle a message.
(Q)uit program.
Choose a option to begin: q
Goodbye!

这是我的完整代码,请解释为什么我的菜单要重新打印,我的 while 循环是否出错,或者我的代码中有什么不合适的地方?

def hw8():

    print('(S)huffle a message.')
    print('(U)nshuffle a message.')
    print('(Q)uit program.')

    x = input('Choose a option to begin: ')

    if x == 'Q' or x == 'q':
        print('Goodbye!')

    while x != 'q' or 'Q' :

        if x == 'S' or x == 's':
            y = input('Enter a message to shuffle: ')

            q1 = ''

            for i in y:
                if ord(i) in range(65,90) or ord(i) in range(97,122):
                    q = chr(ord(i) + 1)
                    q1 = q1 + q
                elif ord(i) == 90:
                    q = chr(ord(i) + 7)
                    q1 = q1 + q
                elif ord(i) == 122:
                    q = 'A'
                    q1 = q1 + q
                else:
                    q = i
                    q1 = q1 + q
            print(q1)



        if x == 'U' or x == 'u':
            f = input('Enter a message to unshuffle: ')

            t2 = ''

            for i in f:
                if ord(i) in range (66,91) or ord(i) in range(98,123):
                    t = chr(ord(i) - 1)
                    t2 = t2 + t
                elif ord(i) == 65:
                    t = 'z'
                    t2 = t2 + t
                elif ord(i) == 97:
                    t = 'Z'
                    t2 = t2 + t
                else:
                    t = i
                    t2 = t2 + t

            print(t2)

        print('(S)huffle a message.')
        print('(U)nshuffle a message.')
        print('(Q)uit program.')

        x = input('Choose a option to continue: ')


hw8()

我希望程序在改组消息或解组消息后以及开始时显示菜单,但不是在用户通过选择“q”要求退出程序后显示菜单。


编辑代码:

def hw8():

    print('(S)huffle a message.')
    print('(U)nshuffle a message.')
    print('(Q)uit program.')

    x = input('Choose a option to begin: ')

    while x != 'q' or x != 'Q' :

        if x == 'S' or x == 's':
            y = input('Enter a message to shuffle: ')

            q1 = ''

            for i in y:
                if ord(i) in range(65,90) or ord(i) in range(97,122):
                    q = chr(ord(i) + 1)
                    q1 = q1 + q
                elif ord(i) == 90:
                    q = chr(ord(i) + 7)
                    q1 = q1 + q
                elif ord(i) == 122:
                    q = 'A'
                    q1 = q1 + q
                else:
                    q = i
                    q1 = q1 + q
            print(q1)



        if x == 'U' or x == 'u':
            f = input('Enter a message to unshuffle: ')

            t2 = ''

            for i in f:
                if ord(i) in range (66,91) or ord(i) in range(98,123):
                    t = chr(ord(i) - 1)
                    t2 = t2 + t
                elif ord(i) == 65:
                    t = 'z'
                    t2 = t2 + t
                elif ord(i) == 97:
                    t = 'Z'
                    t2 = t2 + t
                else:
                    t = i
                    t2 = t2 + t

            print(t2)

        print('(S)huffle a message.')
        print('(U)nshuffle a message.')
        print('(Q)uit program.')

        x = input('Choose a option to continue: ')

        if x == 'Q' or x == 'q':
            print('Goodbye!')


hw8()

新输出:

>>> ================================ RESTART ================================
>>> 

(S)huffle a message.
(U)nshuffle a message.
(Q)uit program.
Choose a option to begin: s
Enter a message to shuffle: hello
ifmmp
(S)huffle a message.
(U)nshuffle a message.
(Q)uit program.
Choose a option to continue: q
Goodbye!
(S)huffle a message.
(U)nshuffle a message.
(Q)uit program.
Choose a option to continue: 
4

2 回答 2

4

x != 'q' or 'Q'被处理为(x != 'q') or 'Q',并且 'Q' 始终为 True。

最好是: x not in 'qQ'x.lower() != 'q'

于 2012-11-27T00:32:17.580 回答
0

你的问题是这一行:

while x != 'q' or 'Q' :

问题是它Q本身总是返回True,所以表达式总是为真。尝试使用以下命令更改行:

while x != 'q' and x != 'Q' :
于 2012-11-27T00:31:52.737 回答